nay
consider rolling two dice.what is the probability that the sum is odd given that one dice shows a 3?
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julie
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well, you could brute force this
julie
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so assuming it's a six sided dice...
julie
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there are six possibilities for the other die
julie
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3+1 = 4 [even] 3+2 = 5 [odd] 3+ 3 = 6 [even] 3+ 4 = 7 [odd] 3 + 5 = 8 [even] 3 + 6 = 9 [odd]
julie
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so you know the roll of one of the dice is a three
julie
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looks to me there are 3 options that get you odd, 3 that give you even
julie
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in sum
julie
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(so 3/6 possibilities for the second die to make an odd number) = 50%
nay
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ohhhhh ok i get it
julie
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that's generally how these work - you want to consider <success case>/<total possibilities> - especially given all possibilities are equally likely e.g. a fair die
nay
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oh wow i wish my teacher would have put it that way
julie
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good to hear, good luck!
nay
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thanks goin