You are given one function, which is \(y = 3x - 1\). This tells you that the slope for the second line must be 3 in order for it to be parallel.
The only thing you have left to find out then is the y-intercept that will let the line go through the point (-3, -5).
A point is a pair, (x, y) that gives you an X value and Y value that are on the line. Since you have m, you can say:
$$ y = 3x + b $$
$$ (-5) = 3 \cdot (-3) + b $$
Here we plugged in the point that we want to be on the line -- (-3, -5) -- into our equation. Then, we can solve for b:
$$ -5 - (3 \cdot (-3)) = b $$
This will give us the value of b, which we can then plug back into the equation:
$$ y = 3x + (-5 - (3 \cdot (-3))) $$