How do you write the equation of the line parallel to y=3x-1 that passes through the point (-3, -5)?
Stacey Warren - Expert brainly.com
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parallel means identical slopes, so m=3, and using pt-slope form, Y-Y1=m(x-x1), the parallel line is Y+5=3(X+3)
Y=3X+4 is the eqtn.
Wow. Dude can um you explain that to me?
So, two lines are only parallel if they have the same slopes.
You can write a simple line in the form y = mx + b, where m is the slope and b is the y-intercept -- the y value the graph of the function runs through when x = 0.
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You are given one function, which is \(y = 3x - 1\). This tells you that the slope for the second line must be 3 in order for it to be parallel.
The only thing you have left to find out then is the y-intercept that will let the line go through the point (-3, -5).
A point is a pair, (x, y) that gives you an X value and Y value that are on the line. Since you have m, you can say:
$$ y = 3x + b $$
$$ (-5) = 3 \cdot (-3) + b $$
Here we plugged in the point that we want to be on the line -- (-3, -5) -- into our equation. Then, we can solve for b:
$$ -5 - (3 \cdot (-3)) = b $$
This will give us the value of b, which we can then plug back into the equation:
$$ y = 3x + (-5 - (3 \cdot (-3))) $$