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anonymous
 5 years ago
How do you write the equation of the line parallel to y=3x1 that passes through the point (3, 5)?
anonymous
 5 years ago
How do you write the equation of the line parallel to y=3x1 that passes through the point (3, 5)?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0parallel means identical slopes, so m=3, and using ptslope form, YY1=m(xx1), the parallel line is Y+5=3(X+3) so Y=3X+95 So........................Y=3X+4 Y=3X+4 is the eqtn.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wow. Dude can um you explain that to me?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0So, two lines are only parallel if they have the same slopes. You can write a simple line in the form y = mx + b, where m is the slope and b is the yintercept  the y value the graph of the function runs through when x = 0.

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0You are given one function, which is \(y = 3x  1\). This tells you that the slope for the second line must be 3 in order for it to be parallel. The only thing you have left to find out then is the yintercept that will let the line go through the point (3, 5). A point is a pair, (x, y) that gives you an X value and Y value that are on the line. Since you have m, you can say: $$ y = 3x + b $$ $$ (5) = 3 \cdot (3) + b $$ Here we plugged in the point that we want to be on the line  (3, 5)  into our equation. Then, we can solve for b: $$ 5  (3 \cdot (3)) = b $$ This will give us the value of b, which we can then plug back into the equation: $$ y = 3x + (5  (3 \cdot (3))) $$
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