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anonymous

  • 5 years ago

find two consecutive odd numbers such that the sum of three sevenths of the first numberand one third of the second numberis equal to 38

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  1. shadowfiend
    • 5 years ago
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    So you want \(\frac{3}{7}x + \frac{1}{3}y = 38\), where x and y are consecutive odd numbers. The fact that they are consecutive odd numbers means that the relationship between the two can be described as \(x = y + 2\) (or vice versa). That means you have: $$ x = y + 2 $$ $$ \frac{3}{7}x + \frac{1}{3}y = 38 $$ Can you figure out how to solve this using systems of equations?

  2. anonymous
    • 5 years ago
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    im confused

  3. sandra
    • 5 years ago
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    hmmm, well in this question you have two unknowns, the first number and the second number

  4. sandra
    • 5 years ago
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    (let's call them x and y). according to the second part of your prompt, we know 3x/7 + y/3 = 38 - that's what shadowfiend wrote too

  5. sandra
    • 5 years ago
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    now, given that the numbers are consecutive, odd numbers, you have another equation you can write too

  6. sandra
    • 5 years ago
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    since all consecutive odd numbers are two numbers apart (since every other number is even), you know the second number (y) is y = x + 2

  7. sandra
    • 5 years ago
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    if you substitute that in for y in the first equation, you should have the answer

  8. sandra
    • 5 years ago
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    or rather, you'll be able to solve for x

  9. sandra
    • 5 years ago
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    and then consequently you'll be able to get y (by substituting the actual value of x into either equation)

  10. anonymous
    • 5 years ago
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    thank you :)

  11. sandra
    • 5 years ago
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    yep no problem, the good thing is once you think you've solved these, they're easy to check, since you just put the numbers back into your equations and make sure the statements are true

  12. shadowfiend
    • 5 years ago
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    Thanks for covering, sandra, great explanation :)

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