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anonymous

  • 5 years ago

In 5 days a 10.0mg sample of radioactive material decays to 3.5mg. based on this information what is the half life?

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  1. shadowfiend
    • 5 years ago
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    Hm. Do you have an exponential decay function to work with?

  2. anonymous
    • 5 years ago
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    Current quantity = original quantity times e raised to the power (elaspsed time / half life), if I remember correctly, or \[Q=Q _{0}e ^{t/h}\]. Plug in and solve for half life; you have everything else you need.

  3. anonymous
    • 5 years ago
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    Oops. I think my exponent is missing a k, specifically -ln(2). So the correct exponent, if I'm right, is e^(-t ln2)/h

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