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anonymous
 5 years ago
givne a matrix A m by n.....there exist matrices C and D such that such that cA = I of n by n and AD = I m by m
prove that C=D and m =n
anonymous
 5 years ago
givne a matrix A m by n.....there exist matrices C and D such that such that cA = I of n by n and AD = I m by m prove that C=D and m =n

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the problem is one of inverse matrices. given \[AA^{1} = A^{1}A=I_x\] where x is the dimension of a square matrix, the rest should follow

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Suppose A is an m n matrix and there exist matrices C and D such that CA = In and AD = Im. Prove that m = n and C = D.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[X_{mn}Y_{kl}=Z_{ml}\] and \[n=m\] for any matrices X,Y Since \[I_n\] is a square matrix \A_{mn}C_{xy}=I_{n} \quad n=x,\text { and }m=y=n \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[A_{mn}C_{xy}=I_{n} \quad n=x,\text { and }m=y=n \]
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