anonymous
  • anonymous
how do I find the integral of sqrt(16x - x^2)?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Not sure I could do it by hand anymore, but in a book of integrals, we find INT(SQRT(2ax-x^2)dx. That's your integral, with a=8. The answer is quite lengthy; too long for me to type. Worst case, get it from integrals.com or wolframalpha.com.
anonymous
  • anonymous
Like LBickford the answer is kind of complicated but here are the steps. (1) Complete the square inside the square root--SQRT(64- (x-8)^2) (2) Use u substitution-- u=x-8 (3) Use z substitution-- z = \[\sin \theta\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.