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anonymous
 5 years ago
6x^(6) + 8x^(4)  15x^(3)  20x
anonymous
 5 years ago
6x^(6) + 8x^(4)  15x^(3)  20x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you look at the exponents on each term, you notice the first two are even and the last two are odd. you will need to incorporate a grouping strategy. first factor out the great common factor of each of the first two terms of coefficients and then factor out the lowest factor of x of the first two terms also, you should be left with a linear (or nearly linear factor) \[6x^{6} + 8x^{4}\] what is the greatest common factor of 6 and 8? what is the lowest factor of those exponents? what are you left over with?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you do the same with \[15x^{3}  20x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops i meant least common factor* sorry!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so what is the least common multiple*** of 6 and 8?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dude let her figure it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok shirl...ignore what i said up there about the greatest common factor or whatever... what is the least common multiple of 6 and 8?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is going on here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok no least common multiple...i.e.. a factor of 6 and 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dude thats not even the correct answer so shes wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok the least common multiple of 6 and 8 is 2 why? because you can factor out a 2 from 6 and 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is the name of my organization

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how can 2 be a multiple of 6 and 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok i was wondering........

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you going to help me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so now look at the exponents of x \[x^{6} and x^{4}\] which one is lower?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think she left dude

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm trying to help you... ok here's a question: can you factor x^4 from x^6 ? answer: yes because x^4(x^2) = x^6 so what you do with the first two terms is factor out the lowest exponent and greatest common factor*** from the ones with the even terms you get : 2x^4 (3x^2 +4) 5x(3x^2 + 4) now if you look at this what do you see in common between the odd and even exponents that were not there before? the factor (3x^2 + 4) now because you are using the grouping idea you can also group the 2x^4 and the 5x. then you can factor (2x^4  5x) to x(2x5) the final answer is x(3x^2 +4)(2x5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u explained well robots! ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks...if that doesn't make sense then i can try to explain it again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well it made sense to me atleast!
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