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anonymous

  • 5 years ago

6x^(6) + 8x^(4) - 15x^(3) - 20x

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  1. anonymous
    • 5 years ago
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    if you look at the exponents on each term, you notice the first two are even and the last two are odd. you will need to incorporate a grouping strategy. first factor out the great common factor of each of the first two terms of coefficients and then factor out the lowest factor of x of the first two terms also, you should be left with a linear (or nearly linear factor) \[6x^{6} + 8x^{4}\] what is the greatest common factor of 6 and 8? what is the lowest factor of those exponents? what are you left over with?

  2. anonymous
    • 5 years ago
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    you do the same with \[-15x^{3} - 20x\]

  3. anonymous
    • 5 years ago
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    gcf 48

  4. anonymous
    • 5 years ago
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    oops i meant least common factor* sorry!

  5. anonymous
    • 5 years ago
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    ok so what is the least common multiple*** of 6 and 8?

  6. anonymous
    • 5 years ago
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    tht would be 24

  7. anonymous
    • 5 years ago
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    dude let her figure it out

  8. anonymous
    • 5 years ago
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    oh sorry my bad

  9. anonymous
    • 5 years ago
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    robot and toast

  10. anonymous
    • 5 years ago
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    ok shirl...ignore what i said up there about the greatest common factor or whatever... what is the least common multiple of 6 and 8?

  11. anonymous
    • 5 years ago
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    what is going on here

  12. anonymous
    • 5 years ago
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    24

  13. anonymous
    • 5 years ago
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    good job shirl

  14. anonymous
    • 5 years ago
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    what is mathpath

  15. anonymous
    • 5 years ago
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    ok no least common multiple...i.e.. a factor of 6 and 8

  16. anonymous
    • 5 years ago
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    dude thats not even the correct answer so shes wrong

  17. anonymous
    • 5 years ago
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    r u sure

  18. anonymous
    • 5 years ago
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    ok the least common multiple of 6 and 8 is 2 why? because you can factor out a 2 from 6 and 8

  19. anonymous
    • 5 years ago
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    it is the name of my organization

  20. anonymous
    • 5 years ago
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    how can 2 be a multiple of 6 and 8

  21. anonymous
    • 5 years ago
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    i meant factor

  22. anonymous
    • 5 years ago
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    oh ok i was wondering........

  23. anonymous
    • 5 years ago
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    are you going to help me

  24. anonymous
    • 5 years ago
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    ok so now look at the exponents of x \[x^{6} and x^{4}\] which one is lower?

  25. anonymous
    • 5 years ago
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    i think she left dude

  26. anonymous
    • 5 years ago
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    i'm trying to help you... ok here's a question: can you factor x^4 from x^6 ? answer: yes because x^4(x^2) = x^6 so what you do with the first two terms is factor out the lowest exponent and greatest common factor*** from the ones with the even terms you get : 2x^4 (3x^2 +4) -5x(3x^2 + 4) now if you look at this what do you see in common between the odd and even exponents that were not there before? the factor (3x^2 + 4) now because you are using the grouping idea you can also group the 2x^4 and the -5x. then you can factor (2x^4 - 5x) to x(2x-5) the final answer is x(3x^2 +4)(2x-5)

  27. anonymous
    • 5 years ago
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    u explained well robots! ;)

  28. anonymous
    • 5 years ago
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    thanks...if that doesn't make sense then i can try to explain it again

  29. anonymous
    • 5 years ago
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    well it made sense to me atleast!

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