A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Hey guys, Find an equation of the straight line that is tangent to the graph of f(x)=√x+1 and parallel to x6y+4=0.
anonymous
 5 years ago
Hey guys, Find an equation of the straight line that is tangent to the graph of f(x)=√x+1 and parallel to x6y+4=0.

This Question is Closed

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0So to do this, you need to rewrite \(x  6y + 4\) into a form where you can easily find the slope (\(y = mx + b\)). Once you have the slope, you'll have to set up \(y = mx + b\) again, with the \(m\) you found above, and plugging in \(\sqrt{x + 1}\) for \(y\), so \(\sqrt{x + 1} = mx + b\), with \(m\) from the previous step, and solve for b.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.