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anonymous
 5 years ago
50000x x is the amount of in $ ann invested in the account that pays 2.5% annual interset
anonymous
 5 years ago
50000x x is the amount of in $ ann invested in the account that pays 2.5% annual interset

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok what are you trying to solve for?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0she invests 50,000 in two interst bearing accounts one pays 2.5 % interst and the second 3.75% at the end of one year the interest ann has earned on these is 1656.25 $ how much she invest in each of the accounts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what in an interest account, each year you earn the % of interest according to your original investment

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so from the first account, she will earn 2.5% of 50,000

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0from the second account, she will earn 3.75% of 50,000

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or sorry, bad first assumption

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we have two equations based on this information:

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0both involve amounts x and y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we know that .025x + .0375y = 1656.25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is, the interest earned between the two accounts adds up to 1656.25, and by definition .025 of X is earned, and .0375 of y is earned in that year

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the other thing we know is that the total amount she invests is 50,000, so x + y = 50,000

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now since you have two variables, and two equations, you can use substitution to solve this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so using the second equation, we know that y = 50,000  x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have to give a vebal descritpion of 50000x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure what you mean by verbal description

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but we know that 50000  x is the amount invested in one of the banks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it says give a verbal description of what each of the follwoing expression represetn in the context of the problem letting x=2.5 %. 50,000 is the interest in the two accounts together

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0she earned a total on the investements $1656.25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right. so what is the expression? 50,000  x is the amount of money invested in the second bank, if we assume x is the amount invested in the 2.5% account

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we know that because the total amounts are equal to 50000

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and if x is the amount in the first account, 50000  y is the amount in the 3.75% account

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i still dont get it but i think i understand ur saying if both x and y equally to 50000 than if you take away .025 away from that than it will give you the answer correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i need to know how to write it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if she has a total at the end of the year of 1656.25 it is asking how much did she invest in both accounts with one being 0.025 and one being 0.0375 annual interest

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Since: 1. x + y = 50000 2. .025x + .0375y = 1656.25 We substitute for y in the second equation, using the first. i.e. y = 50000 x Now substitute for y .025x + .0375 (50000  x) = 1656.25. .025x + 1875  .0375x = 1656.25 .0125x = 1656.25  1875 .0125x = 218.75 x = 218.75/.0125 x = 17500

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so looking above, she invested 17,500 in the bank with 2.5% interest rate (also known as .025 interest)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now that you've solved for one of the values, you can solve for the other (y) by sticking this result back into either equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since x = 17500, 17500 + y = 50000

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so she invested 32500 in the second bank

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(the one with .0375 interest)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now the final part is  check the answer. that is, at the end of the year, do those two values give you the correct total earned interest

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so .025*17500 + 32500*.0375 = 437.50 + 1218.75 = 1656.25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we know it's right
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