krystal
  • krystal
50000-x x is the amount of in $ ann invested in the account that pays 2.5% annual interset
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
ok what are you trying to solve for?
krystal
  • krystal
she invests 50,000 in two interst bearing accounts one pays 2.5 % interst and the second 3.75% at the end of one year the interest ann has earned on these is 1656.25 $ how much she invest in each of the accounts
anonymous
  • anonymous
ok got it!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so what in an interest account, each year you earn the % of interest according to your original investment
anonymous
  • anonymous
so from the first account, she will earn 2.5% of 50,000
anonymous
  • anonymous
from the second account, she will earn 3.75% of 50,000
anonymous
  • anonymous
or sorry, bad first assumption
anonymous
  • anonymous
so we have two equations based on this information:
anonymous
  • anonymous
both involve amounts x and y
anonymous
  • anonymous
we know that .025x + .0375y = 1656.25
anonymous
  • anonymous
that is, the interest earned between the two accounts adds up to 1656.25, and by definition .025 of X is earned, and .0375 of y is earned in that year
anonymous
  • anonymous
the other thing we know is that the total amount she invests is 50,000, so x + y = 50,000
anonymous
  • anonymous
now since you have two variables, and two equations, you can use substitution to solve this
anonymous
  • anonymous
so using the second equation, we know that y = 50,000 - x
krystal
  • krystal
i have to give a vebal descritpion of 50000-x
anonymous
  • anonymous
I'm not sure what you mean by verbal description
anonymous
  • anonymous
but we know that 50000 - x is the amount invested in one of the banks
krystal
  • krystal
it says give a verbal description of what each of the follwoing expression represetn in the context of the problem letting x=2.5 %. 50,000 is the interest in the two accounts together
krystal
  • krystal
she earned a total on the investements $1656.25
anonymous
  • anonymous
right. so what is the expression? 50,000 - x is the amount of money invested in the second bank, if we assume x is the amount invested in the 2.5% account
anonymous
  • anonymous
we know that because the total amounts are equal to 50000
anonymous
  • anonymous
so x+y = 50000
anonymous
  • anonymous
y = 50000 - x
anonymous
  • anonymous
and if x is the amount in the first account, 50000 - y is the amount in the 3.75% account
anonymous
  • anonymous
is that helping?
krystal
  • krystal
i still dont get it but i think i understand ur saying if both x and y equally to 50000 than if you take away .025 away from that than it will give you the answer correct
krystal
  • krystal
i need to know how to write it out
krystal
  • krystal
if she has a total at the end of the year of 1656.25 it is asking how much did she invest in both accounts with one being 0.025 and one being 0.0375 annual interest
anonymous
  • anonymous
Since: 1. x + y = 50000 2. .025x + .0375y = 1656.25 We substitute for y in the second equation, using the first. i.e. y = 50000 -x Now substitute for y .025x + .0375 (50000 - x) = 1656.25. .025x + 1875 - .0375x = 1656.25 -.0125x = 1656.25 - 1875 -.0125x = -218.75 x = -218.75/-.0125 x = 17500
anonymous
  • anonymous
so looking above, she invested 17,500 in the bank with 2.5% interest rate (also known as .025 interest)
anonymous
  • anonymous
now that you've solved for one of the values, you can solve for the other (y) by sticking this result back into either equation
anonymous
  • anonymous
so x+5 = 50000
anonymous
  • anonymous
*x + y
anonymous
  • anonymous
since x = 17500, 17500 + y = 50000
anonymous
  • anonymous
y = 32500
anonymous
  • anonymous
so she invested 32500 in the second bank
anonymous
  • anonymous
(the one with .0375 interest)
anonymous
  • anonymous
now the final part is - check the answer. that is, at the end of the year, do those two values give you the correct total earned interest
anonymous
  • anonymous
so .025*17500 + 32500*.0375 = 437.50 + 1218.75 = 1656.25
anonymous
  • anonymous
so we know it's right
anonymous
  • anonymous
make sense?
krystal
  • krystal
kinda

Looking for something else?

Not the answer you are looking for? Search for more explanations.