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  • 5 years ago

Find Three consecutive integers such that the square of the second increased by the third is 43

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  1. sid1729
    • 5 years ago
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    They are 3 consecutive integers. Let the first one be X, the second will be X + 1 and the third will be X + 2. Now, according to the problem statement, the square of the second is (X+1)^2. Increasing this by the third means : \[(x+1)^2+(x+2) \] where (X + 2) is the third number. So, the equation is : \[(x+1)^2 + (x+2) = 43\] Solve it for x, and you can get the three consecutive integers.

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