## anonymous 5 years ago Ok I have this math problem: 3x^2=4^2+x^2 Can you help me solve for x and show me the steps?

1. anonymous

2. anonymous

$3x^2 = 4^2 + x^ 2$

3. anonymous

right? ok, so there is an x term on either side, luckily they are both the same operation on x

4. anonymous

you should move the x terms to one side, try the getting all the x terms on the left side

5. anonymous

ok if i did that then it would take the [x^2\] from the 3

6. anonymous

right, so the left side would be 2x^2 = 4^2....

7. anonymous

2x^2 = 4*4 = 2*2*2*2, divide both sides by 2 => x^2 = 2*2*2 => solve for x...

8. anonymous

$3 x ^{2} = 4^{2}+x^{2} \rightarrow 2x^{2} = 4^{2}$ Then $4^{2}= 16 \rightarrow x^{2} = 8 \right arrow x = \pm 2 \sqrt{2}$

9. anonymous

[\4^{2} = 16 \rightarrow x^{2} = 8 \rightarrow x = +\] or $- 2 \sqrt{2}$

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