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anonymous

  • 5 years ago

Ok I have this math problem: 3x^2=4^2+x^2 Can you help me solve for x and show me the steps?

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    \[3x^2 = 4^2 + x^ 2\]

  3. anonymous
    • 5 years ago
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    right? ok, so there is an x term on either side, luckily they are both the same operation on x

  4. anonymous
    • 5 years ago
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    you should move the x terms to one side, try the getting all the x terms on the left side

  5. anonymous
    • 5 years ago
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    ok if i did that then it would take the [x^2\] from the 3

  6. anonymous
    • 5 years ago
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    right, so the left side would be 2x^2 = 4^2....

  7. anonymous
    • 5 years ago
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    2x^2 = 4*4 = 2*2*2*2, divide both sides by 2 => x^2 = 2*2*2 => solve for x...

  8. anonymous
    • 5 years ago
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    \[3 x ^{2} = 4^{2}+x^{2} \rightarrow 2x^{2} = 4^{2}\] Then \[ 4^{2}= 16 \rightarrow x^{2} = 8 \right arrow x = \pm 2 \sqrt{2} \]

  9. anonymous
    • 5 years ago
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    [\4^{2} = 16 \rightarrow x^{2} = 8 \rightarrow x = +\] or \[- 2 \sqrt{2}\]

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