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anonymous
 5 years ago
Can anyone help with this one
4/x +7 = 2/3x Thank you!!
anonymous
 5 years ago
Can anyone help with this one 4/x +7 = 2/3x Thank you!!

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shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0So you have: \[\frac{4}{x} + 7 = \frac{2}{3x}\] We can actually multiply through by \(x\): \[4 = 7x + \frac{2}{3}\]

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Er, sorry: \[4 + 7x = \frac{2}{3}\]

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Can you solve that equation a little more easily?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you so much...giving that a try.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but that's not right...what am I doing wrong?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Try plugging back into the original equation: \[\begin{align} \frac{4}{\frac{10/21}} + 7 &= \frac{2}{3\frac{10}{21}}\\ \frac{4\cdot 21}{10} + 7 &= \frac{2\cdot 21}{30}\\ \frac{84}{10} + \frac{70}{10} &= \frac{42}{30}\\ \frac{84 + 70}{10} &= \frac{14}{10}\\ \frac{14}{10} &= \frac{14}{10} \end{align}\]

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Whoops. Sorry about that. \[\begin{align} \frac{4}{\frac{10}{21}} + 7 &= \frac{2}{3\frac{10}{21}}\\ \frac{4\cdot 21}{10} + 7 &= \frac{2\cdot 21}{30}\\ \frac{84}{10} + \frac{70}{10} &= \frac{42}{30}\\ \frac{84 + 70}{10} &= \frac{14}{10}\\ \frac{14}{10} &= \frac{14}{10} \end{align}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0must have plugged it in wrong....thanks so much! I may be back : )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hey, Do you think you could help with one more?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so generally you want to multiply by the greatest power in a denominator so that you can have no \(x\) in the denominators. What is that in this case?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks. Sorry, Im multitasking so I keep walking away. So multiply by \[x^{2}\] ?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0That's okay :) Yes, that's right. So what would that make the equation look like?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Exactly. Do you think you can solve that one?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0That's what I got too :) Remember to doublecheck it by plugging it into the original equation and making sure the equality holds true.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0shadow can u help me in the question i asked earlier
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