anonymous
  • anonymous
Can anyone help with this one 4/x +7 = 2/3x Thank you!!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
shadowfiend
  • shadowfiend
So you have: \[\frac{4}{x} + 7 = \frac{2}{3x}\] We can actually multiply through by \(x\): \[4 = 7x + \frac{2}{3}\]
shadowfiend
  • shadowfiend
Er, sorry: \[4 + 7x = \frac{2}{3}\]
shadowfiend
  • shadowfiend
Can you solve that equation a little more easily?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Thank you so much...giving that a try.
shadowfiend
  • shadowfiend
Cool :)
anonymous
  • anonymous
I got -10/21
anonymous
  • anonymous
but that's not right...what am I doing wrong?
shadowfiend
  • shadowfiend
That is right!
shadowfiend
  • shadowfiend
Try plugging back into the original equation: \[\begin{align} \frac{4}{\frac{-10/21}} + 7 &= \frac{2}{3\frac{-10}{21}}\\ \frac{4\cdot 21}{-10} + 7 &= \frac{2\cdot 21}{-30}\\ \frac{84}{-10} + \frac{70}{10} &= \frac{42}{-30}\\ \frac{-84 + 70}{10} &= \frac{-14}{10}\\ \frac{-14}{10} &= \frac{-14}{10} \end{align}\]
shadowfiend
  • shadowfiend
Whoops. Sorry about that. \[\begin{align} \frac{4}{\frac{-10}{21}} + 7 &= \frac{2}{3\frac{-10}{21}}\\ \frac{4\cdot 21}{-10} + 7 &= \frac{2\cdot 21}{-30}\\ \frac{84}{-10} + \frac{70}{10} &= \frac{42}{-30}\\ \frac{-84 + 70}{10} &= \frac{-14}{10}\\ \frac{-14}{10} &= \frac{-14}{10} \end{align}\]
anonymous
  • anonymous
must have plugged it in wrong....thanks so much! I may be back : )
shadowfiend
  • shadowfiend
Awesome! :)
anonymous
  • anonymous
Hey, Do you think you could help with one more?
anonymous
  • anonymous
1/x - 5/x^2 = 8/5x
shadowfiend
  • shadowfiend
Ok, so generally you want to multiply by the greatest power in a denominator so that you can have no \(x\) in the denominators. What is that in this case?
anonymous
  • anonymous
Thanks. Sorry, Im multi-tasking so I keep walking away. So multiply by \[x^{2}\] ?
shadowfiend
  • shadowfiend
That's okay :) Yes, that's right. So what would that make the equation look like?
anonymous
  • anonymous
x-5 = 8x/5
shadowfiend
  • shadowfiend
Exactly. Do you think you can solve that one?
anonymous
  • anonymous
Thanks, I'll try.
shadowfiend
  • shadowfiend
Cool :)
anonymous
  • anonymous
x= -25/3
shadowfiend
  • shadowfiend
That's what I got too :) Remember to double-check it by plugging it into the original equation and making sure the equality holds true.
anonymous
  • anonymous
shadow can u help me in the question i asked earlier
anonymous
  • anonymous
not the same 1

Looking for something else?

Not the answer you are looking for? Search for more explanations.