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anonymous
 5 years ago
the greater of the numbers is 3 times the smaller. their sum is 44.
anonymous
 5 years ago
the greater of the numbers is 3 times the smaller. their sum is 44.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so 1. x = 3*y 2. x + y = 44

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so now what you want to realize, is that you can just combine all those y's

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok right, so 3*y can also be written as 3y. basically in words this means "I have 3 ys"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if I "have three oranges", and I add one orange

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0same thing with unknown variables

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03*y by definition means 3 multiplied by Y, or Y multiplied by 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just like 3*2 means "I have three 2's"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03*2 = 6 because 2+2+2 = 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's the very definition of multiplication

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so shorthand, we write that as 3y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and so 3y + y = (y+y+y) + y = 44

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0some examples: 3y+y = 4y 2x + 2x = 4x x+2x = 3x x + x = 2x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so in your example, we got to 3y+y = 44

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so can you solve for y from there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we are not multiplying the 3*2y?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because the 3 is referring to 3 times the first y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if it helps you visualize, use parentheses when you substitute

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so when we substitute , we have (3*y) + y = 44

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03*y is the same thing as 3y  just be convention people usually leave off the multiplication symbol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we have (3y) + y = 44

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and now we need to divide both sides by 4, to get y alone

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so I'm going to ask you a few follow ups. what is 5y + 5y?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is just for practice

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i was confused bcuz i added the 2 ys that i saw and then tried to multiply

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0great what is 5y + 1y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and now what is 5*y + y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0exactly =) because multiplication is always first

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what you were doing was 5 * (y+y) , essentially

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but what you wanted was 5*y + y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so now you got it though =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so for the one we just did 44,11?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, if 11 is y, then what is X?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you need to substitute 11 for y in any of the first equations

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0good work =). I know the word problems can be frustrating, but believe me it's worth struggling through these until you have it down.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is really the foundation for a lot of higher level math.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. i hope i remeber this. do u have any tips to remember

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, practice. and for these problems, three rules to remember: 1. Always try and turn the word problems into equations 2. You can perform the same operation on both sides of the equation and have both sides always still be equal 3. If you have two equations, and two unknown variables, you always just need to substitute one equation into the other (you can pick either variable)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04. You can always combine like terms  i.e. 3y + y = 4y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and at the end, once you think you've solved the problem, you can ALWAYS check your work

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you just told me that the bigger number is 33, and the smaller number is 11

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can put both of those numbers back into your original equations, and see if the equations are true

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if they are, then you were right!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if not, then you go back and see where you messed up a bit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but for these types of problems, you should never be asking yourself if you were right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you should be able to put your answers back into the equations, and see if they hold true

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that will definitely help if i check my work

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey hip, I have to go for now! but keep trying, keep asking here, and I'll be back around.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm glad I could help a bit!. good luck, you'll get there for sure

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you helped A LOT!! thank you so much
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