A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Why is ds/dt of s=t/9t+2 = 2/(9t+2)^2 and not the derivative 9x^2+2?
anonymous
 5 years ago
Why is ds/dt of s=t/9t+2 = 2/(9t+2)^2 and not the derivative 9x^2+2?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Basically, I answered the question with 9x^2+2, but I was wrong and I'm trying to figure out why. :(

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Well, when you have an equation divided by another equation, you have to apply the quotient rule or the chain rule. I prefer the chain rule, personally. So: \[\frac{t}{9t + 2} = t^{1}(9t + 2)\] If you apply the chain rule to that, the answer might make a bit more sense.

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Well, chain rule + product rule.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So would t/5t+1 be equal to 2/(5t+1)^2?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Heh, I totally messed the thing up there up. \[\frac{t}{9t + 2} = t(9t + 2)^{1}\]

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0No, it wouldn't derive to that. It would derive to 1/(5t + 1)^2.

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0You do this by saying: \[\frac{ds}{dt}t(5t+1)^{1}\] \[\begin{align} (5t + 1)^{1} + t(1)(5t + 1)^{2}(5)\\ \frac{1}{5t + 1}  \frac{5t}{(5t + 1)^2}\\ \frac{5t + 1}{(5t+1)^2}  \frac{5t}{(5t + 1)^2}\\ \frac{5t + 1  5t}{(5t + 1)^2}\\ \frac{1}{(5t + 1)^2} \end{align}\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.