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anonymous

  • 5 years ago

find the value of y. express in simplest radical form.

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  1. shadowfiend
    • 5 years ago
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    This question doesn't make sense alone. Is there an equation involved?

  2. anonymous
    • 5 years ago
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    a triangle

  3. anonymous
    • 5 years ago
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    the hypotenuse is \[\sqrt{85}\] the base is y and the height is 6

  4. shadowfiend
    • 5 years ago
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    Ok. So if it has a hypotenuse, then it is a right triangle. What equation did we say relates the sides of a right triangle?

  5. anonymous
    • 5 years ago
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    i dont know

  6. shadowfiend
    • 5 years ago
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    The Pythagorean theorem. Check the previous answer I gave you for what that looks like, and then let's continue.

  7. anonymous
    • 5 years ago
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    ok but i never have done it with a radical of 85

  8. shadowfiend
    • 5 years ago
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    Ok, so that's fine. Once we've said that \(a^2 + b^2 = c^2\), and we know that the hypotenuse is \(\sqrt{85}\), we have: \[y^2 + 6^2 = \sqrt{85}^2\] What's \(\sqrt{85}^2\)?

  9. anonymous
    • 5 years ago
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    about 28

  10. shadowfiend
    • 5 years ago
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    Not quite. The square root is the opposite of squaring something. So a square root and a square cancel out.

  11. anonymous
    • 5 years ago
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    so it cancels all the time?

  12. shadowfiend
    • 5 years ago
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    Right. So in \(\sqrt{x}^2 = x\). In this case, 85. So we have: \[y^2 + 6^2 = 85\] Then you can solve for \(y\).

  13. anonymous
    • 5 years ago
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    y2 + 65 = 85

  14. shadowfiend
    • 5 years ago
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    \(6^2 = 6 \cdot 6\), which isn't quite 65.

  15. anonymous
    • 5 years ago
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    i mean 36

  16. shadowfiend
    • 5 years ago
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    Right :)

  17. shadowfiend
    • 5 years ago
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    Exactly.

  18. anonymous
    • 5 years ago
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    so now subtract 65 from both sides?

  19. shadowfiend
    • 5 years ago
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    Well, 36 :)

  20. anonymous
    • 5 years ago
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    yea

  21. anonymous
    • 5 years ago
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    y2=49

  22. anonymous
    • 5 years ago
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    \[\sqrt{49}\]

  23. anonymous
    • 5 years ago
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    7

  24. shadowfiend
    • 5 years ago
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    Pwned. Exactly.

  25. anonymous
    • 5 years ago
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    wow why cant my teacher explain this like this easy way

  26. shadowfiend
    • 5 years ago
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    That's a question I can't answer :)

  27. anonymous
    • 5 years ago
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    haha yea

  28. anonymous
    • 5 years ago
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    shadow what if the radical 19 is not the hypatenuse but its the height or base do i still keep 19 or do i do 19 x 19

  29. shadowfiend
    • 5 years ago
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    When you plug into the quadratic equation, you'll still have it squared. So if it's \(\sqrt{19}\), then when you square it it will become 19.

  30. anonymous
    • 5 years ago
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    ok thank you do you do trigonometry sin cos and tangent?

  31. shadowfiend
    • 5 years ago
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    Sometimes. I saw your other question, but not sure what you're asking. Add some more details to it if you can.

  32. anonymous
    • 5 years ago
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    where do i find my other question?

  33. anonymous
    • 5 years ago
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    found it

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