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find the value of y. express in simplest radical form.

Mathematics
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This question doesn't make sense alone. Is there an equation involved?
a triangle
the hypotenuse is \[\sqrt{85}\] the base is y and the height is 6

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Other answers:

Ok. So if it has a hypotenuse, then it is a right triangle. What equation did we say relates the sides of a right triangle?
i dont know
The Pythagorean theorem. Check the previous answer I gave you for what that looks like, and then let's continue.
ok but i never have done it with a radical of 85
Ok, so that's fine. Once we've said that \(a^2 + b^2 = c^2\), and we know that the hypotenuse is \(\sqrt{85}\), we have: \[y^2 + 6^2 = \sqrt{85}^2\] What's \(\sqrt{85}^2\)?
about 28
Not quite. The square root is the opposite of squaring something. So a square root and a square cancel out.
so it cancels all the time?
Right. So in \(\sqrt{x}^2 = x\). In this case, 85. So we have: \[y^2 + 6^2 = 85\] Then you can solve for \(y\).
y2 + 65 = 85
\(6^2 = 6 \cdot 6\), which isn't quite 65.
i mean 36
Right :)
Exactly.
so now subtract 65 from both sides?
Well, 36 :)
yea
y2=49
\[\sqrt{49}\]
7
Pwned. Exactly.
wow why cant my teacher explain this like this easy way
That's a question I can't answer :)
haha yea
shadow what if the radical 19 is not the hypatenuse but its the height or base do i still keep 19 or do i do 19 x 19
When you plug into the quadratic equation, you'll still have it squared. So if it's \(\sqrt{19}\), then when you square it it will become 19.
ok thank you do you do trigonometry sin cos and tangent?
Sometimes. I saw your other question, but not sure what you're asking. Add some more details to it if you can.
where do i find my other question?
found it

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