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first you find the common denomiator of (1/x)-(1/y) then you flip it and multiply it by x+y/x-y
Can you demonstrate please?
do you mind if i give you a generic version. I would rather you understand then just give you the answer. Is that ok?
That would be great
I have gotten to (xy) x+y over (x-y) (y-x) is there anything else I can do?
na your done
Thanks for your help!
the only thing you could do is factor a negative out. and make it x-y squared on the bottom but that isnt necesary
What about if you have 5p/6p? can u cancel the p's?
And also s-1 over (s-1) (s+1) can you cancel the s-1's?
I'm not too sure about the canceling rules...
which math are you in? If you dont mind me asking.
ok so the general rule in dividing variables is. if it is the same variable you subtract the exponents.
Oh im in algebra 2
Ok got that
So could u cancel the p's or s-1's?
what is the exponent of the p's and x-1's?
I guess it is just one because the exponents canceled out earlier
what is anything raised to the 0 power except 0^0
for instance what is x^0?
is it one?
But they are not to the oth power!
really? If (x-4)^1/(X-4)^1=(X-4)^0 then (x-4)^0=1
just to give you a hint i am a math tutor my statements are meant to lead you somewhere i am not asking you questions for no reason lol
ok thats cool, im still confused tho!
so x^2/X^2 you subtract the exponenets leaving you with x^0 right?
can you do (x-4)^2/(x-4) for me?
treat the x-4 as one thing and just worry about the exponenets
(x-4) (x-4)/(x-4) equals x-4?
what you just did was the subtracted the exponenets. do you understand what i mean?
YES! Hooray, so that should mean you can cancel the p's and the s-1's?
what do you think?
I am only saying that because i want you to be confident.
I think it is a yes......
im ok with that =)
sorry this took so long i really want you to understand it
Thank u for taking the time to help me! I really appreciate it 8 )
no problem. I like this place. i will probably hang around, so if you have more questions feel free to ask.
Haha im sure i will! nite