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anonymous
 5 years ago
I'm doing rational expressions and need help please! How do you simplify: x+y/xy divided by 1/x 1/y. Thanks!
anonymous
 5 years ago
I'm doing rational expressions and need help please! How do you simplify: x+y/xy divided by 1/x 1/y. Thanks!

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Salt
 5 years ago
Best ResponseYou've already chosen the best response.0first you find the common denomiator of (1/x)(1/y) then you flip it and multiply it by x+y/xy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you demonstrate please?

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0do you mind if i give you a generic version. I would rather you understand then just give you the answer. Is that ok?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have gotten to (xy) x+y over (xy) (yx) is there anything else I can do?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks for your help!

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0the only thing you could do is factor a negative out. and make it xy squared on the bottom but that isnt necesary

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What about if you have 5p/6p? can u cancel the p's?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And also s1 over (s1) (s+1) can you cancel the s1's?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not too sure about the canceling rules...

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0which math are you in? If you dont mind me asking.

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0ok so the general rule in dividing variables is. if it is the same variable you subtract the exponents.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So could u cancel the p's or s1's?

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0what is the exponent of the p's and x1's?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I guess it is just one because the exponents canceled out earlier

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0what is anything raised to the 0 power except 0^0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But they are not to the oth power!

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0really? If (x4)^1/(X4)^1=(X4)^0 then (x4)^0=1

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0just to give you a hint i am a math tutor my statements are meant to lead you somewhere i am not asking you questions for no reason lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thats cool, im still confused tho!

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0so x^2/X^2 you subtract the exponenets leaving you with x^0 right?

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0can you do (x4)^2/(x4) for me?

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0treat the x4 as one thing and just worry about the exponenets

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x4) (x4)/(x4) equals x4?

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0what you just did was the subtracted the exponenets. do you understand what i mean?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0YES! Hooray, so that should mean you can cancel the p's and the s1's?

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0I am only saying that because i want you to be confident.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think it is a yes......

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0sorry this took so long i really want you to understand it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank u for taking the time to help me! I really appreciate it 8 )

Salt
 5 years ago
Best ResponseYou've already chosen the best response.0no problem. I like this place. i will probably hang around, so if you have more questions feel free to ask.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha im sure i will! nite
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