## anonymous 5 years ago how do you find the first derivative of p=4 + x^2 all over 4 - x^2

1. anonymous

$p=(4+x^2)/4-x^2=1+1/4x^2-x^2=1-3/4x^2$ $p \prime=-3/4*2*x=-3x/2$ i hope i didn't do any mistake

2. anonymous

this is incorrect: if the original equation is: $(4 + x^2) / (4 - x^2)$

3. anonymous

you can consider this as $4/(4-x^2) + (x^2)/(4-x^2)$

4. anonymous

dad0gg, can we get some more clarification when you get back here?