## anonymous 5 years ago for what values of k is lim x---> infinity sinhkx/cosh2x finite

1. anonymous

use the defintion of sinh and cosh: $\sinh(x) = {1/2} (e^{x}-e^{-x})$ $\cosh(x) = {1/2} (e^{x}+e^{-x})$ $\lim_{x \rightarrow \infty} (e^{kx}-e^{-kx})/(e^{2x}+e^{-2x})$

2. anonymous