## anna 5 years ago what is the value of theta here,, 4sin2theta=0

$4\times \sin (2\theta) = 0$ If you divide both sides by 4, you get: $\frac{4 \times \sin(2\theta)}{4} = \frac{0}{4}$ which reduces to $\sin (2\theta) = 0$ Now, what are the values where the sin function can be zero? These values are : 0,$\pi, 2\pi, 3\pi, 4\pi.....npi$ where n is a natural number Thus, $2\theta = 0, \pi, 2\pi, 3\pi, 4\pi, .... npi$ You can divide both sides by two to get the answer.