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anonymous
 5 years ago
I have a very hard question (for myself...)
x2[x3(x+4)5]=3{2x[x8(x4)]}2
please help :)
anonymous
 5 years ago
I have a very hard question (for myself...) x2[x3(x+4)5]=3{2x[x8(x4)]}2 please help :)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x2[x3(x+4)5] = 3(2x[x8(x4)])2\] wow, lots of groups!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, so let's think about what the goal is, the goal is unite the groups on each side then solve for x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0adfriedman, nice but so fast!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it was just expanding brackets

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right, ok fastff, a good approach could be to work from the inside out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0focus on the left side: x−2[x−3(x+4)−5]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so let's start in the middle of this with 3(x+4)...can you expand this please?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nice. so the equation is now x−2[x−(3x+12)−5] = x2[x3x125]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the really quick approach is to note that only constants multiply the bracketed terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, now simplify the expression with the [ ... ]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0almost...forgot about the x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you have x3x125....ok

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0simplify this: start with the xterms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0aren't we suppose to distribute?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so inside the [ ] you have x3x125 which becomes 2x17, right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0fastff, how's it going?
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