anonymous
  • anonymous
For what value k are the graphs y= -1 over 2 x+ 6 and 4y - kx =-28
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
ARe the graphs what...? equal?
anonymous
  • anonymous
perpemdicular
anonymous
  • anonymous
y=-(1/2) x +6 Is this the first equation? or is it y=-1/(2x+6)

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anonymous
  • anonymous
I am going to assume you meant the first equation above and if that is the case then the slopes must be negative reciprocals if they are perpendicular. So set each equation y=...and then set the slope of one equal to the negative reciprocal of the other. solving it this way then k=-8

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