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anonymous

  • 5 years ago

For what value k are the graphs y= -1 over 2 x+ 6 and 4y - kx =-28

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  1. anonymous
    • 5 years ago
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    ARe the graphs what...? equal?

  2. anonymous
    • 5 years ago
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    perpemdicular

  3. anonymous
    • 5 years ago
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    y=-(1/2) x +6 Is this the first equation? or is it y=-1/(2x+6)

  4. anonymous
    • 5 years ago
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    I am going to assume you meant the first equation above and if that is the case then the slopes must be negative reciprocals if they are perpendicular. So set each equation y=...and then set the slope of one equal to the negative reciprocal of the other. solving it this way then k=-8

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spraguer (Moderator)
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