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megan

  • 5 years ago

how do you solve sectheta/csctheta

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  1. Megan
    • 5 years ago
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    anyone?

  2. anonymous
    • 5 years ago
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    have you converted these into their equivalent e functions?

  3. anonymous
    • 5 years ago
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    oops are you referring to hyperbolics? maybe not. If not just use your trig identities and simplify sec / csc

  4. Mack
    • 5 years ago
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    hey shadowfiend come to the chat and let us chat

  5. anonymous
    • 5 years ago
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    you could do it with e functions as sin(x) = (e^(ix)-e^(-ix)) / (2i), but this isn't a very pretty way to solve it. Use your 1/Cos(x) = Sec(x) and 1/Sin(x) = Csc(x), then see if you recognize the new quotient...

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