megan
  • megan
how do you solve sectheta/csctheta
Mathematics
schrodinger
  • schrodinger
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megan
  • megan
anyone?
anonymous
  • anonymous
have you converted these into their equivalent e functions?
anonymous
  • anonymous
oops are you referring to hyperbolics? maybe not. If not just use your trig identities and simplify sec / csc

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mack
  • mack
hey shadowfiend come to the chat and let us chat
anonymous
  • anonymous
you could do it with e functions as sin(x) = (e^(ix)-e^(-ix)) / (2i), but this isn't a very pretty way to solve it. Use your 1/Cos(x) = Sec(x) and 1/Sin(x) = Csc(x), then see if you recognize the new quotient...

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