ok is this permutation or combination and how many possible outcomes r there. writing a four digit # usingthe #s 0-9 with no repeats

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ok is this permutation or combination and how many possible outcomes r there. writing a four digit # usingthe #s 0-9 with no repeats

Mathematics
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permutation= order matters...and combination=order does matter. If you are writing a 4 digit number, order does matter because what goes in the first place will effect the second number, and the first and second will affect the 3rd..and so on. since there are no repeats therefore it is a permutation
but whats the answer
you multiply the number of choices you have for each digit together

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for example first digit 10 choices second digit 9 choices (since no repeats)
so it would be 9 times 8 times 7 times 6
well the first digit has 10 choices since there are 10 numbers from 0 to 9... so its 10 times 9 times 8 times 7
the answer in the back of the book says the answer is 35 how is that possible
how is that possible
hm....let me think about that
is that the whole question? or is there some missing information?
thats it
ayms its fine i will figure it out later i have 2 periods to figure it out tomorrow
i dont think it's 35. I'm pretty sure its 5040
actually it is not 10*9*8*7, the first digit may not be a 0 as that would be a 3 digit number, it is 9*9*8*7=4536

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