anonymous
  • anonymous
ok is this permutation or combination and how many possible outcomes r there. writing a four digit # usingthe #s 0-9 with no repeats
Mathematics
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schrodinger
  • schrodinger
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anonymous
  • anonymous
permutation= order matters...and combination=order does matter. If you are writing a 4 digit number, order does matter because what goes in the first place will effect the second number, and the first and second will affect the 3rd..and so on. since there are no repeats therefore it is a permutation
anonymous
  • anonymous
but whats the answer
anonymous
  • anonymous
you multiply the number of choices you have for each digit together

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anonymous
  • anonymous
for example first digit 10 choices second digit 9 choices (since no repeats)
anonymous
  • anonymous
so it would be 9 times 8 times 7 times 6
anonymous
  • anonymous
well the first digit has 10 choices since there are 10 numbers from 0 to 9... so its 10 times 9 times 8 times 7
anonymous
  • anonymous
the answer in the back of the book says the answer is 35 how is that possible
anonymous
  • anonymous
how is that possible
anonymous
  • anonymous
hm....let me think about that
anonymous
  • anonymous
is that the whole question? or is there some missing information?
anonymous
  • anonymous
thats it
anonymous
  • anonymous
ayms its fine i will figure it out later i have 2 periods to figure it out tomorrow
anonymous
  • anonymous
i dont think it's 35. I'm pretty sure its 5040
anonymous
  • anonymous
actually it is not 10*9*8*7, the first digit may not be a 0 as that would be a 3 digit number, it is 9*9*8*7=4536

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