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anonymous

  • 5 years ago

Linear Algebra : Cⁿ(complex number)is a vector space over field R(real number).

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  1. anonymous
    • 5 years ago
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    can i get some help please .......

  2. anonymous
    • 5 years ago
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    what is the question asking to be found about the vector space?

  3. anonymous
    • 5 years ago
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    i need proof....

  4. anonymous
    • 5 years ago
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    i've only ever bothered proving this as part of a relation to a matrix. I think you have to show it's closed under addition and multiplication and to itself, using z = a +ib with a and b in the reals, show for complex y and z, y+z and y*z are complex. I've only ever bothered showing by relation to the matrix: Z = [a -b] <=> z = a+ib [b a] you then use matrix algebra to show Z <=> z in closure of addition and multiplication

  5. anonymous
    • 5 years ago
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    oh and scalar

  6. anonymous
    • 5 years ago
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    thank you

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spraguer (Moderator)
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