anonymous
  • anonymous
I'm having trouble...I have to factor n^2 + n + 16...
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Well that expression alone is a prime factor within the Real numbers set.
anonymous
  • anonymous
Tho in the Complex set it has this two factors: \[n ^{2}+n+16=\left( n+0.5\left( 1+\sqrt{-47} \right) \right)\left( n+0.5\left( 1-\sqrt{-47} \right) \right)\]
anonymous
  • anonymous
.... which are found by use of the quadratic formula

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anonymous
  • anonymous
Depending on the type or problem, you'll just want to use the "completing the square" method, and just create a perfect factor.

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