anonymous
  • anonymous
factorise x^3-x^2-5x-3=o
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
i usually attempt this type of question by trial and error. Usually my choice of guess is range from -3 to 3. Since, using x=3 is one of the factor, it help reduce the equation to this form; x^2 + 2x +1. you can solve the above equation using quadratic formula; x^3-x^2-5x-3 = (x-3)(x^2 + 2x + 1) = (x-3)(x-1)^2
anonymous
  • anonymous
to find a root you could use newton's method: x(n+1) = x(n) - f(x(n))/f'(x(n)) if you have a ti calculator try this: 2->x enter x - (x^3-x^2-5x-3)/(3x^2-2x-5) -> x enter (5 times) you should see it approach 3. This is a good way if you can't really think of a root but have a calculator. Then proceed by division as kenius describes.
anonymous
  • anonymous
where "->" is the "sto>" button

Looking for something else?

Not the answer you are looking for? Search for more explanations.