anonymous
  • anonymous
(1+0.095/12)^12=(1+i/2)^2 ..... dont know why but I keep getting stuck on this...please help! thnx
Mathematics
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anonymous
  • anonymous
(1+0.095/12)^12=(1+i/2)^2 ..... dont know why but I keep getting stuck on this...please help! thnx
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Ok, remember the phrase" Please Excuse My Dear Aunt Sally"? It was made to remember the order of operations, which is "Parenthesis, Exponentials, Multiplication, Division, Addition, Subtraction) which should be done in that order. So start inside the parenthesis \(1+0.095/12)^12\ which is \1.00791667^12\. \(1+i/2)^2 = 1.09924763\ Now since you can't simplify the inside any more, foil out the \(1+i/2)\ \(1 +i/2 + i^2/4) = 1.09924763\ Now subtract the one across \i^2/4 + i/2 = .09924763\ Notice how it's close to form of the quadratic equation? Subtract the right side and get it to the left: \i^2/4 + i/2 - .09924763 = 0\ and now I'd use quadratic method to solve it. Hope this helps! (I hope I didn't foul anything up, hopefully someone will come by and check it, as I haven't had my coffee yet.)

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