I need help solving: One number is 4 more than another. IF 6 times the smaller minus 4 times the larger is 4, what are the two numbers.

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We have simultaneous equations: \[ x = y + 4 \] and \[ 6y - 4x = 4 \]

Thanks gentoolx. Ok I get that, are they solved separately, or is one solved before the other?

So, you can just substitute the value from first equation (x value) to the second equation or you can transform the first to \[ x-y=4 \] and then: \[4x-4y=16\] Then you sum up these two equations to get \[2y = 20 \] Then you compute value of y and then you substitute it to one of the original equations to compute x.

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