## anonymous 5 years ago Can anyone help stuck on differentiation question y= 5 sin 2x

1. anonymous

I guess that you have to differentiate function $f(x)=5sin2x$ So, you have to use two differentiation rules: constant rule and chain rule. The first is because you have 5 as a constant. This constant is factored out and it doesn't play role in the main part of work. The main part of work uses chain rule on $sin2x$ To use it we have to substitute 2x by $u$ and this gives us $sin u$ Now, use the chain rule ${df \over dx} = {df \over du} * {du \over dx}$

2. anonymous

Thanks will try it

3. anonymous

You're welcome. Remember to multiply by factored constant in the end.

4. anonymous

3x+(-7)=-11+(-11)

5. anonymous

3x+(-7)=-11+(-11)

6. anonymous

Well, $3x - 7 = -22$ then add seven to both sides $3x = -15$ Finally divide both sides by three $x = -5$