Solve equation: (d+2)(d-5)=-6

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Solve equation: (d+2)(d-5)=-6

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Can anyone help!!!
i think its d^2 - 5d + 2d - 10 = -6 d^2-3d-10=-6 d^2-3d=4
and d = -2 or d= 5

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Other answers:

well, these are easier to solve if you expand them and then factor them back out once you have something that equals zero
so for example, if you use foil, you get:
d^2 -5d + 2d -10 = -6
d^2 -3d -4 = 0
now that you have the right side equal to zero, you can factor back out
and get (d+1)(d-4) = 0
so once you have a factored left hand side that equals zero, you know that the solutions are the two values that make either of the left hand components zero
since zero times anything is zero
so one of the solutions is d=-1
can you get the other now?

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