Two boats leave a port at the same time, one going north and other traveling south. The northbound boat travles 16 mph faster than the southbound boat. If the southbound boat is traveling at 47 mph, how long will it be before they are 1430 miles apart?

- anonymous

- schrodinger

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- anonymous

r u in geometry

- anonymous

No i am im in elementry algerbra

- anonymous

can you help me with this, its a little confusing

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## More answers

- anonymous

i know i have tried to solve it many times let me keep trying

- anonymous

r u still there

- anonymous

hello?

- anonymous

i have the answer

- anonymous

Yeah I am here sorry, How did you do it?

- anonymous

okay so the first thing you want to do is compare the two and make a relationship

- anonymous

there are two things that the boats have in common the the rate unit and the distance right

- anonymous

Right!

- anonymous

so the formula that ties speed, time, and distance is d=st

- anonymous

right

- anonymous

distance = speed times time

- anonymous

yeah, I forgot to put the formula

- anonymous

time can also be represented as a rate in this case we have mph

- anonymous

Okay so would you now set the equation up

- anonymous

therefore it would be appropriate to say distance= speed times rate

- anonymous

so one boat is going x mph the other boat is going 16+x

- anonymous

x=47
and 16+47 is 63

- anonymous

the only thing that ties these two boats together is the distance so we can assume the equation will be equal to 1430 or the distance

- anonymous

right

- anonymous

Yes that true!

- anonymous

the other side would be related because it shares a common unit the rate or mph

- anonymous

therefore 1430=rt+rt

- anonymous

the rates are 63 mph and 47 mph

- anonymous

t = time

- anonymous

so the final equation looks like 1430=63t+ 47t

- anonymous

1430=110t

- anonymous

1430/110=t

- anonymous

Its would be 13!

- anonymous

Thanks Dude!

- anonymous

it would be 13 hours

- anonymous

yes, your welcome if you have any other questions i can help

- anonymous

Okay Well that was my last problem though But if I have anymore question I will ask away!

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