anonymous
  • anonymous
Two boats leave a port at the same time, one going north and other traveling south. The northbound boat travles 16 mph faster than the southbound boat. If the southbound boat is traveling at 47 mph, how long will it be before they are 1430 miles apart?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
r u in geometry
anonymous
  • anonymous
No i am im in elementry algerbra
anonymous
  • anonymous
can you help me with this, its a little confusing

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anonymous
  • anonymous
i know i have tried to solve it many times let me keep trying
anonymous
  • anonymous
r u still there
anonymous
  • anonymous
hello?
anonymous
  • anonymous
i have the answer
anonymous
  • anonymous
Yeah I am here sorry, How did you do it?
anonymous
  • anonymous
okay so the first thing you want to do is compare the two and make a relationship
anonymous
  • anonymous
there are two things that the boats have in common the the rate unit and the distance right
anonymous
  • anonymous
Right!
anonymous
  • anonymous
so the formula that ties speed, time, and distance is d=st
anonymous
  • anonymous
right
anonymous
  • anonymous
distance = speed times time
anonymous
  • anonymous
yeah, I forgot to put the formula
anonymous
  • anonymous
time can also be represented as a rate in this case we have mph
anonymous
  • anonymous
Okay so would you now set the equation up
anonymous
  • anonymous
therefore it would be appropriate to say distance= speed times rate
anonymous
  • anonymous
so one boat is going x mph the other boat is going 16+x
anonymous
  • anonymous
x=47 and 16+47 is 63
anonymous
  • anonymous
the only thing that ties these two boats together is the distance so we can assume the equation will be equal to 1430 or the distance
anonymous
  • anonymous
right
anonymous
  • anonymous
Yes that true!
anonymous
  • anonymous
the other side would be related because it shares a common unit the rate or mph
anonymous
  • anonymous
therefore 1430=rt+rt
anonymous
  • anonymous
the rates are 63 mph and 47 mph
anonymous
  • anonymous
t = time
anonymous
  • anonymous
so the final equation looks like 1430=63t+ 47t
anonymous
  • anonymous
1430=110t
anonymous
  • anonymous
1430/110=t
anonymous
  • anonymous
Its would be 13!
anonymous
  • anonymous
Thanks Dude!
anonymous
  • anonymous
it would be 13 hours
anonymous
  • anonymous
yes, your welcome if you have any other questions i can help
anonymous
  • anonymous
Okay Well that was my last problem though But if I have anymore question I will ask away!

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