## anonymous 5 years ago how to find the indefinite integral of (x^2-1)/x

Use a calculator noob... (x^2-1)/x can be rewritten as (x^2)/x -1/x split up the integral $\int\limits_{?}^{?}x - \int\limits_{?}^{?}1/x = x^2/2 + \ln \left| x \right| + c$