## anonymous 5 years ago d=square root of (square root 2 -5 sr 2)^2 +(- sr 3 - seven sr 3)^2

1. anonymous

all right. the equations is. $d = \sqrt{2 - 5 \sqrt{2}} + (-\sqrt{3} - 7 * \sqrt{3})^2$

2. anonymous

is that right?

3. anonymous

well, the 1st sr is over the whole problem....

4. anonymous

nm.....duh

5. anonymous

I've been doing this hw since yesterday, I'm in a dark zone....I am just feed up with gettin to a prob. then stuck, which thats been all 87 prob.

6. anonymous

sorry can you try rewriting the problem

7. anonymous

there are a lot of sqrt's and I can't tell which numbers of grouped under square roots and not, o_0...

8. anonymous

$d=\sqrt (\sqrt 2-5\sqrt2)^2+(-\sqrt 3 -7\sqrt3)^2$

9. anonymous

It sqrt's the whole equation.... make sence? I hope

10. anonymous

ok

11. anonymous

so, let's start with each paranthetical group, focusing on the left one with root(2)

12. anonymous

can you evaluate $\sqrt{2} - 5\sqrt{2}$

13. anonymous

got lost...yep

14. anonymous

-4$-4\sqrt 2$

15. anonymous

now square it

16. anonymous

$-8\sqrt3$

17. anonymous

thats where I'm lost....how do you ^2 a sqrt?

18. anonymous

ok, so a square root is just this: you have a number, x, that you multiply by itself, x * x, to yield another value, x*x = y, so the square root of y is x.

19. anonymous

$do you 16*2 then ^2 or do you ^ the 4 and the 2 separate?$

20. anonymous

square root of 2 is actually a value less than two. if you have multiply $\sqrt{2} * \sqrt{2}$ you'll get 2

21. anonymous

so in that case you had, y = x*x, so the square root of y is x, here you could say that y =2, therefore x = $\sqrt{2}$

22. anonymous

so you get 16 * 2 then square?

23. anonymous

16 *2 is the result of $-4\sqrt{?}$ sqaured

24. anonymous

sorry, that ? is a 2

25. anonymous

i'm confused as to why you square it again?

26. anonymous

you've solved the left paranthetical group, so solve the right

27. anonymous

$d=\sqrt (x2 -x1)^2 +(y2-y1)^2$ right?

28. anonymous

this is the distance equation, yes

29. anonymous

did you solve the problem?

30. anonymous

1024+36864 right?

31. anonymous

sqrt? right?

32. anonymous

so you have 16*2 on the left and what on the right? i get 64 * 3 on the right

33. anonymous

so that is 16*2 + 64*3

34. anonymous

squareroot( 16 *2 + 64*3 ), unless there are other operations missing in the original equation...

35. anonymous

Sorry! I keep gettin stuck with trin to post my comments to you!! I got 1024 + 36864 then sqrt 37288? am I right so far?

36. anonymous

i think the numbers you have are way too big, how did you get 1024?

37. anonymous

I squared the 16*2 and 64*3....?

38. anonymous

Are you still with me? If not then thanx for all your help...if you are then am I right or wher am I going wrong?

39. anonymous

why did you square them?

40. anonymous

you already did, that's how you have 16*2 and not -4*sqrt(2)

41. anonymous

look at the prob again.....in th () you have to get the sqrt down to be squared...

42. anonymous

If not then how do you ^ 2 a sqrt?

43. anonymous

a sqrt is just a number that if you square that number, you get another number...so if you have $\sqrt{2}$, if you square that you get 2. if you "^2 a sqrt" those two operations are cancelling eachother out...so you did this when you found that

44. anonymous

$(-4*\sqrt{2})^2 = 16 * 2$

45. anonymous

right there you squared a square root

46. anonymous

oh, ok....

47. anonymous

rt(2) squared is 2

48. anonymous

so how do I do the -8 sqrt 3 ^2?

49. anonymous

the same way as you did with the left, ;) so what is -8 squared?

50. anonymous

64

51. anonymous

what is $\sqrt{3}$ squared?

52. anonymous

3?

53. anonymous

right

54. anonymous

so you have 16*2 + 64*3

55. anonymous

so i sqrt 160?

56. anonymous

you have 32 + 192

57. anonymous

that is the value you square root

58. anonymous

the 32 is negative?

59. anonymous

no.....

60. anonymous

both value are positive, they were calculated from negative values that you then squared, and when you multiply two negative numbers you get a positive

61. anonymous

So d=14.96?

62. anonymous

right, $\sqrt{204}$

63. anonymous

So you are in Georgia IT?

64. anonymous

65. anonymous

$\sqrt{224}$

66. anonymous

yes, i am

67. anonymous

68. anonymous

where are you from?

69. anonymous

Great Help!! Thanx more than you'll ever know!! Good ol' Tennessee

70. anonymous

right on, no problem, :)

71. anonymous

Maybe you can help me again soon!! God Bless!

72. anonymous

of course, would be glad too

73. anonymous

thanks