anonymous
  • anonymous
d=square root of (square root 2 -5 sr 2)^2 +(- sr 3 - seven sr 3)^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
all right. the equations is. \[d = \sqrt{2 - 5 \sqrt{2}} + (-\sqrt{3} - 7 * \sqrt{3})^2\]
anonymous
  • anonymous
is that right?
anonymous
  • anonymous
well, the 1st sr is over the whole problem....

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anonymous
  • anonymous
nm.....duh
anonymous
  • anonymous
I've been doing this hw since yesterday, I'm in a dark zone....I am just feed up with gettin to a prob. then stuck, which thats been all 87 prob.
anonymous
  • anonymous
sorry can you try rewriting the problem
anonymous
  • anonymous
there are a lot of sqrt's and I can't tell which numbers of grouped under square roots and not, o_0...
anonymous
  • anonymous
\[ d=\sqrt (\sqrt 2-5\sqrt2)^2+(-\sqrt 3 -7\sqrt3)^2\]
anonymous
  • anonymous
It sqrt's the whole equation.... make sence? I hope
anonymous
  • anonymous
ok
anonymous
  • anonymous
so, let's start with each paranthetical group, focusing on the left one with root(2)
anonymous
  • anonymous
can you evaluate \[\sqrt{2} - 5\sqrt{2}\]
anonymous
  • anonymous
got lost...yep
anonymous
  • anonymous
-4\[-4\sqrt 2\]
anonymous
  • anonymous
now square it
anonymous
  • anonymous
\[-8\sqrt3\]
anonymous
  • anonymous
thats where I'm lost....how do you ^2 a sqrt?
anonymous
  • anonymous
ok, so a square root is just this: you have a number, x, that you multiply by itself, x * x, to yield another value, x*x = y, so the square root of y is x.
anonymous
  • anonymous
\[do you 16*2 then ^2 or do you ^ the 4 and the 2 separate?\]
anonymous
  • anonymous
square root of 2 is actually a value less than two. if you have multiply \[\sqrt{2} * \sqrt{2}\] you'll get 2
anonymous
  • anonymous
so in that case you had, y = x*x, so the square root of y is x, here you could say that y =2, therefore x = \[\sqrt{2}\]
anonymous
  • anonymous
so you get 16 * 2 then square?
anonymous
  • anonymous
16 *2 is the result of \[-4\sqrt{?}\] sqaured
anonymous
  • anonymous
sorry, that ? is a 2
anonymous
  • anonymous
i'm confused as to why you square it again?
anonymous
  • anonymous
you've solved the left paranthetical group, so solve the right
anonymous
  • anonymous
\[d=\sqrt (x2 -x1)^2 +(y2-y1)^2\] right?
anonymous
  • anonymous
this is the distance equation, yes
anonymous
  • anonymous
did you solve the problem?
anonymous
  • anonymous
1024+36864 right?
anonymous
  • anonymous
sqrt? right?
anonymous
  • anonymous
so you have 16*2 on the left and what on the right? i get 64 * 3 on the right
anonymous
  • anonymous
so that is 16*2 + 64*3
anonymous
  • anonymous
squareroot( 16 *2 + 64*3 ), unless there are other operations missing in the original equation...
anonymous
  • anonymous
Sorry! I keep gettin stuck with trin to post my comments to you!! I got 1024 + 36864 then sqrt 37288? am I right so far?
anonymous
  • anonymous
i think the numbers you have are way too big, how did you get 1024?
anonymous
  • anonymous
I squared the 16*2 and 64*3....?
anonymous
  • anonymous
Are you still with me? If not then thanx for all your help...if you are then am I right or wher am I going wrong?
anonymous
  • anonymous
why did you square them?
anonymous
  • anonymous
you already did, that's how you have 16*2 and not -4*sqrt(2)
anonymous
  • anonymous
look at the prob again.....in th () you have to get the sqrt down to be squared...
anonymous
  • anonymous
If not then how do you ^ 2 a sqrt?
anonymous
  • anonymous
a sqrt is just a number that if you square that number, you get another number...so if you have \[\sqrt{2}\], if you square that you get 2. if you "^2 a sqrt" those two operations are cancelling eachother out...so you did this when you found that
anonymous
  • anonymous
\[(-4*\sqrt{2})^2 = 16 * 2\]
anonymous
  • anonymous
right there you squared a square root
anonymous
  • anonymous
oh, ok....
anonymous
  • anonymous
rt(2) squared is 2
anonymous
  • anonymous
so how do I do the -8 sqrt 3 ^2?
anonymous
  • anonymous
the same way as you did with the left, ;) so what is -8 squared?
anonymous
  • anonymous
64
anonymous
  • anonymous
what is \[\sqrt{3}\] squared?
anonymous
  • anonymous
3?
anonymous
  • anonymous
right
anonymous
  • anonymous
so you have 16*2 + 64*3
anonymous
  • anonymous
so i sqrt 160?
anonymous
  • anonymous
you have 32 + 192
anonymous
  • anonymous
that is the value you square root
anonymous
  • anonymous
the 32 is negative?
anonymous
  • anonymous
no.....
anonymous
  • anonymous
both value are positive, they were calculated from negative values that you then squared, and when you multiply two negative numbers you get a positive
anonymous
  • anonymous
So d=14.96?
anonymous
  • anonymous
right, \[\sqrt{204}\]
anonymous
  • anonymous
So you are in Georgia IT?
anonymous
  • anonymous
sorry, that wwas poor adding
anonymous
  • anonymous
\[\sqrt{224}\]
anonymous
  • anonymous
yes, i am
anonymous
  • anonymous
was this helpful?
anonymous
  • anonymous
where are you from?
anonymous
  • anonymous
Great Help!! Thanx more than you'll ever know!! Good ol' Tennessee
anonymous
  • anonymous
right on, no problem, :)
anonymous
  • anonymous
Maybe you can help me again soon!! God Bless!
anonymous
  • anonymous
of course, would be glad too
anonymous
  • anonymous
thanks

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