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d=square root of (square root 2 -5 sr 2)^2 +(- sr 3 - seven sr 3)^2

Mathematics
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all right. the equations is. \[d = \sqrt{2 - 5 \sqrt{2}} + (-\sqrt{3} - 7 * \sqrt{3})^2\]
is that right?
well, the 1st sr is over the whole problem....

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Other answers:

nm.....duh
I've been doing this hw since yesterday, I'm in a dark zone....I am just feed up with gettin to a prob. then stuck, which thats been all 87 prob.
sorry can you try rewriting the problem
there are a lot of sqrt's and I can't tell which numbers of grouped under square roots and not, o_0...
\[ d=\sqrt (\sqrt 2-5\sqrt2)^2+(-\sqrt 3 -7\sqrt3)^2\]
It sqrt's the whole equation.... make sence? I hope
ok
so, let's start with each paranthetical group, focusing on the left one with root(2)
can you evaluate \[\sqrt{2} - 5\sqrt{2}\]
got lost...yep
-4\[-4\sqrt 2\]
now square it
\[-8\sqrt3\]
thats where I'm lost....how do you ^2 a sqrt?
ok, so a square root is just this: you have a number, x, that you multiply by itself, x * x, to yield another value, x*x = y, so the square root of y is x.
\[do you 16*2 then ^2 or do you ^ the 4 and the 2 separate?\]
square root of 2 is actually a value less than two. if you have multiply \[\sqrt{2} * \sqrt{2}\] you'll get 2
so in that case you had, y = x*x, so the square root of y is x, here you could say that y =2, therefore x = \[\sqrt{2}\]
so you get 16 * 2 then square?
16 *2 is the result of \[-4\sqrt{?}\] sqaured
sorry, that ? is a 2
i'm confused as to why you square it again?
you've solved the left paranthetical group, so solve the right
\[d=\sqrt (x2 -x1)^2 +(y2-y1)^2\] right?
this is the distance equation, yes
did you solve the problem?
1024+36864 right?
sqrt? right?
so you have 16*2 on the left and what on the right? i get 64 * 3 on the right
so that is 16*2 + 64*3
squareroot( 16 *2 + 64*3 ), unless there are other operations missing in the original equation...
Sorry! I keep gettin stuck with trin to post my comments to you!! I got 1024 + 36864 then sqrt 37288? am I right so far?
i think the numbers you have are way too big, how did you get 1024?
I squared the 16*2 and 64*3....?
Are you still with me? If not then thanx for all your help...if you are then am I right or wher am I going wrong?
why did you square them?
you already did, that's how you have 16*2 and not -4*sqrt(2)
look at the prob again.....in th () you have to get the sqrt down to be squared...
If not then how do you ^ 2 a sqrt?
a sqrt is just a number that if you square that number, you get another number...so if you have \[\sqrt{2}\], if you square that you get 2. if you "^2 a sqrt" those two operations are cancelling eachother out...so you did this when you found that
\[(-4*\sqrt{2})^2 = 16 * 2\]
right there you squared a square root
oh, ok....
rt(2) squared is 2
so how do I do the -8 sqrt 3 ^2?
the same way as you did with the left, ;) so what is -8 squared?
64
what is \[\sqrt{3}\] squared?
3?
right
so you have 16*2 + 64*3
so i sqrt 160?
you have 32 + 192
that is the value you square root
the 32 is negative?
no.....
both value are positive, they were calculated from negative values that you then squared, and when you multiply two negative numbers you get a positive
So d=14.96?
right, \[\sqrt{204}\]
So you are in Georgia IT?
sorry, that wwas poor adding
\[\sqrt{224}\]
yes, i am
was this helpful?
where are you from?
Great Help!! Thanx more than you'll ever know!! Good ol' Tennessee
right on, no problem, :)
Maybe you can help me again soon!! God Bless!
of course, would be glad too
thanks

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