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Denise
 5 years ago
How do you solve (x7)^2+(y(11))^2=6^2
Denise
 5 years ago
How do you solve (x7)^2+(y(11))^2=6^2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[{({x7})^2}+{({y(11)}^2} = {6^2}\] Remember your order of operations: PEMDAS. 1) Simplify the {y(11)} first  remember two consecutive negatives is the same as a plus sign. 2) You can multiply out 6^2 on the right at the same time. 3) Lastly Use your rules to multiply a binomial by a binomial (itself). You'll have two of these to multiply out. 4) Finally, combine like terms. Post your progress.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oops: \[...(11))^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hi Denise, solve for what? you have 2 variables (x and y) in the equation Ivan

Denise
 5 years ago
Best ResponseYou've already chosen the best response.0Ivan, I am suppose to write the centerradius form equation of the circle.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oops, I was telling you how to expand this equation  not very useful. Remember the basic unit circle equation: \[x^2 + y^2 = (radius)^2 \]  radius equals 1 for the unit circle. I imagine that your assignment is to find the new center and radius of the circle in the given equation. Correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just responded, but my answer didnt stick for some reason. I agree with Moss' interpretation. http://www.regentsprep.org/Regents/math/algtrig/ATC1/circlelesson.htm the equation you have, to me, is in the centre radius form, whereas the multiplied out form is the "general form"
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