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high

  • 5 years ago

how can i draw a graph of mod(y)=cosx ???

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  1. sandra
    • 5 years ago
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    hello high

  2. sandra
    • 5 years ago
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    well, mod(y)=cosx is really two separate graphs (well, the same graph, but there are two distinct parts.)

  3. high
    • 5 years ago
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    i think itll look like bubbles

  4. high
    • 5 years ago
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    am not so sure...

  5. shadowfiend
    • 5 years ago
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    Are you sure that's a correct problem? What is `mod'?

  6. high
    • 5 years ago
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    modulus..

  7. high
    • 5 years ago
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    !y!

  8. shadowfiend
    • 5 years ago
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    Yeah sorry. I've never seen mod used that way :)

  9. shadowfiend
    • 5 years ago
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    So you're right if you mean bubbles as in just the parts where cos is above the x axis.

  10. shadowfiend
    • 5 years ago
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    Because the absolute value (or modulus) of y must be positive, by definition, this function isn't defined if y < 0. Since cos(x) is sometimes negative, those parts of the cos(x) plot are not valid for this particular function, because they don't make any sense.

  11. shadowfiend
    • 5 years ago
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    I am wrong!

  12. high
    • 5 years ago
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    i think so

  13. shadowfiend
    • 5 years ago
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    Ah, I see what you mean about bubbles now. Yes, I think you're correct.

  14. shadowfiend
    • 5 years ago
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    Because negative values of y will mirror the positive values.

  15. high
    • 5 years ago
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    will you please explain?

  16. shadowfiend
    • 5 years ago
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    Well, basically, what the above function means is really two different functions: \[y = \left\{\begin{align}\cos x\text{ when }y >= 0\\\cos y\text{ when }y < 0\end{align}\right.\]

  17. shadowfiend
    • 5 years ago
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    Hm. Sorry: \[y = \left\{\begin{matrix}\cos x\text{ when }y >= 0\\\cos x\text{ when }y < 0\end{matrix}\right.\]

  18. sid1729
    • 5 years ago
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    The function only exists for cos x > 0, because absolute values cannot be negative. There will be two functions: y = cos x -y = cos x so for each x (when cos x >0), you will have two values - one positive and other negative, both having the same absolute numerical value

  19. sid1729
    • 5 years ago
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    take an example: let x be \[\frac{\pi}{2}\] now, y = \[\frac{1}{\sqrt(2)}\] and -y = \[\frac{1}{\sqrt(2)}\] So, we put those two together in the same graph.

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