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anonymous

  • 5 years ago

What is the inverse cotangent of (square root of 3) divided by (3)?

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  1. anonymous
    • 5 years ago
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    \[\cot-1(\sqrt{3}/3) = \pi/3\]

  2. anonymous
    • 5 years ago
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    \[\cot^{-1}(\sqrt{3}/3) = \pi/3\] <-- Fixed your typo. In TeX the "^" symbol only takes the first number after it so you have to put the negative exponents in between braces like this: {-1}. You can right click on the equation to see the TeX formatting.

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