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anonymous
 5 years ago
hi, I'm having some trouble figuring this problem. solve for y.
Z= (XY)/(X+Y)
anonymous
 5 years ago
hi, I'm having some trouble figuring this problem. solve for y. Z= (XY)/(X+Y)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0z(x+y)=xy zx+zyxy=0 zx+y(zx)=0 y(zx)=zx y=(zx)/(zx) finally y=(zx)/(xz) Dont hesitate to ask any question, please.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, it's supposed to be solve for x, i'm sorry.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0change x by y and y by x in the last expression. Is that what you want? Sorry if I dont understand the question (my english is not my mother language) and im just trying to help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i appreciate your help so much, thank you. I want to solve for x, the zx+y(zx)=0 is where i get confused on where to go from there to solve for x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok here I go again ..... There is an infinity of solutions. That is why you cannot list them all. Insted, you have to list x that are not solutions. So the only value of x that is not a solution for the above equation is: X!=y => that is x not equal to zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0CORRECTION There is an infinity of solutions. That is why you cannot list them all. Insted, you have to list x that are not solutions. So the only value of x that is not a solution for the above equation is: X!=y => that is x not equal to Y.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Z(X+Y)=XY ZX+ZY=XY ZXXY=ZY X(ZY)=ZY X=(ZY)/(ZY) X=(ZY)/(YZ) That said, you cannot solve this equation explicitly because you have more variables than equations.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you, you both have been very helpful.
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