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Is this 3x-1 or 3x+1 on the inside of the parentheses? (or neither?)

oops.. +

(3x+1)^3/2=64
3x+1=64^2/3=16
3x=15
x=5

I can see how you did it in my head but on paper what do I do with the 3/2?

You raise both sides of the equation to 2/3 to cancel it out on the left.

ok : )

p.s. Thanks so much!!