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anonymous

  • 5 years ago

Tim and Judy mix two kinds of feed for pedigreed dogs. they wish to make 28 pounds of feed worth $0.19 per pound by mixing one kind worth $0.13 per pound with another worth $0.29 per pound. How many pounds of the cheaper kind should they use in the mix?

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  1. anonymous
    • 5 years ago
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    ok, so from the problem we know after mixing we want the average pound to be worth .19, and that the total number of pounds should be 28

  2. anonymous
    • 5 years ago
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    so we have two unknowns, and hence we need two equations to solve this

  3. anonymous
    • 5 years ago
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    so the first one is that (.13*x + .29*y)/28 = .19

  4. anonymous
    • 5 years ago
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    that is the direct translation of "the average pound costs .19 after adding both components together")

  5. anonymous
    • 5 years ago
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    now the second equation we know, is that when we add the two amounts together, there are a total of 28 pounds

  6. anonymous
    • 5 years ago
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    i.e. x+y = 28

  7. anonymous
    • 5 years ago
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    so now you have to use substitution to get either x or y

  8. anonymous
    • 5 years ago
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    so let's take the second equation's value of "y", which is the more expensive amount, and substitute it back into the first equation

  9. anonymous
    • 5 years ago
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    y = 28 - x

  10. anonymous
    • 5 years ago
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    so if we put that back into the first equation, in place of y ("substituing"), we get: .13x + .29(28 -x) = .19

  11. anonymous
    • 5 years ago
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    can you solve for x from there?

  12. anonymous
    • 5 years ago
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    whoops sorry, above line should ready (.13x + .29(28-x))/28 = .19

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