Tim and Judy mix two kinds of feed for pedigreed dogs. they wish to make 28 pounds of feed worth $0.19 per pound by mixing one kind worth $0.13 per pound with another worth $0.29 per pound. How many pounds of the cheaper kind should they use in the mix?

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- sandra

ok, so from the problem we know after mixing we want the average pound to be worth .19, and that the total number of pounds should be 28

- sandra

so we have two unknowns, and hence we need two equations to solve this

- sandra

so the first one is that (.13*x + .29*y)/28 = .19

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- sandra

that is the direct translation of "the average pound costs .19 after adding both components together")

- sandra

now the second equation we know, is that when we add the two amounts together, there are a total of 28 pounds

- sandra

i.e. x+y = 28

- sandra

so now you have to use substitution to get either x or y

- sandra

so let's take the second equation's value of "y", which is the more expensive amount, and substitute it back into the first equation

- sandra

y = 28 - x

- sandra

so if we put that back into the first equation, in place of y ("substituing"), we get:
.13x + .29(28 -x) = .19

- sandra

can you solve for x from there?

- sandra

whoops sorry, above line should ready (.13x + .29(28-x))/28 = .19

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