• anonymous
use the limit comparison theorem to determine if the following integral diverges or converges: integral from 2 to infinite: (x^2 dx)/[(x-1)^2 * (x+3)]
  • chestercat
See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this
and thousands of other questions

  • anonymous
This is how I'm reading the integral given, the integral of {(x^2)/[(x-1)(x-1)(x+3)]} dx from 2 to a as a grows unbounded (or approaches infinity as many like to say). When x=2, (x^2)/[(x-1)(x-1)(x+3)] is 4/5, and this value is the initial point of the integral. This means this 4/5 is less than or equal to the integral over our given bounds (2+) since the derivative of the polynomial is positive over the same bounds of integration so the integral is constantly getting a little positive addition to it. The integral of 4/5 over the same bound clearly grows unbounded or diverges, and since the integral of 4/5 is smaller at every point within the bounds of integration than the given integral, then the given integral must diverge too.
  • anonymous
mary beth and steve like to shop at a warehouse store .they get a 10% discount on everything they buy.what fractional part of the disscount do they recieve? a.1/20 b.1/10 c.1/510 d.1/520

Looking for something else?

Not the answer you are looking for? Search for more explanations.