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anonymous
 5 years ago
4+(1/x)(1/x^2)=0
anonymous
 5 years ago
4+(1/x)(1/x^2)=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you want me to do

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0solve the equation plz

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got x= 1/2 or x= 1/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or x= 1 +or root 17/ 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got 1 do you mind to check a few others? could you show your work so i can make sure im doing them right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you want me to show the work for the one i just did

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^2(4+(1/x)(1/x^2))=0 gets rid of the denom

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you have 4x^2+x1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then use the quadratic equation to solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry it kicked me off. now can you find the real solution for the same equation plz

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry i thought you left

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tell me what you think you would do for that problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hi would you plz care to answer those 2 ?s only 1 more after that!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well i have that the answer for the problem you just did should be .309 which should be no solution correct? i dont think i worked it right tho

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you mean the 3x(x+2)=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y do u keep leaving i can't help if u keep doin that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and what would the real solution be for 4+(1/x)(1/x^2)=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Its kicking me off sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0college al why does my grade matter

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that was solving that equation. not finding the real solution?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it doesn't i just try to get a feel for who im helping

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the real solution to any equation, like above with a degree of two it will be quadratic that means that the real solution is any point in which that equation crosses the xaxis or in other words the xintercepts the term real refers to any solution that can be graphed on a real plane not including imaginary terms or number

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or if you are finding a solution to a pair of equations the solution represents the point where the two equations intersect

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok and what would the real solution be for 4+(1/x)(1/x^2)=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you haven'y given me any context clues that you are trying to solve two equations intersectio point, that means it will be the xintercepts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, do you have a graphing calc.?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is the first step in trying to solve that equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do not and find a common den

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0almost, we have to rationalize the denomintator, because this equation represents a function and only real solutions which can't have a denom. of zero therefore we must get rid of the variables in the denom.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay. and i would do that by?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0mulitply the entire equation on both sides by the largest variable in the denom.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you should get 4x^2+x1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay and then? i just realized we didnt go over this in class. we skiped this section

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is college algebra?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have never heard of that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm in hs too, that's why i'm asking.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you want me to finish

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright then you would use the quadratic equation to solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what's the next question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the final answer is?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you check it in the original equation to make sure it works

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it works when i checked it, what's the next question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats all i have now. ive already check the others thanks for all your help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, your welcome if you ever need help let me know
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