anonymous
  • anonymous
4+(1/x)-(1/x^2)=0
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
what do you want me to do
anonymous
  • anonymous
solve the equation plz
anonymous
  • anonymous
i got x= -1/2 or x= 1/2

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anonymous
  • anonymous
or x= -1 +or- root 17/ 8
anonymous
  • anonymous
i got 1 do you mind to check a few others? could you show your work so i can make sure im doing them right?
anonymous
  • anonymous
do you want me to show the work for the one i just did
anonymous
  • anonymous
yes plz
anonymous
  • anonymous
and then 3x(x+3)=1
anonymous
  • anonymous
x^2(4+(1/x)-(1/x^2))=0 gets rid of the denom
anonymous
  • anonymous
then you have 4x^2+x-1
anonymous
  • anonymous
then use the quadratic equation to solve
anonymous
  • anonymous
ok
anonymous
  • anonymous
?
anonymous
  • anonymous
???
anonymous
  • anonymous
hello?
anonymous
  • anonymous
okay bye
anonymous
  • anonymous
hello
anonymous
  • anonymous
sorry it kicked me off. now can you find the real solution for the same equation plz
anonymous
  • anonymous
and for 3x(x+2)=1
anonymous
  • anonymous
hi
anonymous
  • anonymous
sry i thought you left
anonymous
  • anonymous
tell me what you think you would do for that problem
anonymous
  • anonymous
hi would you plz care to answer those 2 ?s only 1 more after that!
anonymous
  • anonymous
well i have that the answer for the problem you just did should be .309 which should be no solution correct? i dont think i worked it right tho
anonymous
  • anonymous
you mean the 3x(x+2)=1
anonymous
  • anonymous
hello?
anonymous
  • anonymous
y do u keep leaving i can't help if u keep doin that
anonymous
  • anonymous
and what would the real solution be for 4+(1/x)-(1/x^2)=0
anonymous
  • anonymous
Its kicking me off sorry
anonymous
  • anonymous
look above
anonymous
  • anonymous
what grade r u in?
anonymous
  • anonymous
college al why does my grade matter
anonymous
  • anonymous
that was solving that equation. not finding the real solution?
anonymous
  • anonymous
it doesn't i just try to get a feel for who im helping
anonymous
  • anonymous
high school
anonymous
  • anonymous
the real solution to any equation, like above with a degree of two it will be quadratic that means that the real solution is any point in which that equation crosses the x-axis or in other words the x-intercepts the term real refers to any solution that can be graphed on a real plane not including imaginary terms or number
anonymous
  • anonymous
or if you are finding a solution to a pair of equations the solution represents the point where the two equations intersect
anonymous
  • anonymous
ok and what would the real solution be for 4+(1/x)-(1/x^2)=0
anonymous
  • anonymous
you haven'y given me any context clues that you are trying to solve two equations intersectio point, that means it will be the x-intercepts
anonymous
  • anonymous
ok, do you have a graphing calc.?
anonymous
  • anonymous
what is the first step in trying to solve that equation?
anonymous
  • anonymous
do not and find a common den
anonymous
  • anonymous
almost, we have to rationalize the denomintator, because this equation represents a function and only real solutions which can't have a denom. of zero therefore we must get rid of the variables in the denom.
anonymous
  • anonymous
okay. and i would do that by?
anonymous
  • anonymous
mulitply the entire equation on both sides by the largest variable in the denom.
anonymous
  • anonymous
you should get 4x^2+x-1
anonymous
  • anonymous
okay and then? i just realized we didnt go over this in class. we skiped this section
anonymous
  • anonymous
what is college algebra?
anonymous
  • anonymous
i have never heard of that?
anonymous
  • anonymous
i'm in hs too, that's why i'm asking.
anonymous
  • anonymous
thanks for the help
anonymous
  • anonymous
do you want me to finish
anonymous
  • anonymous
alright then you would use the quadratic equation to solve
anonymous
  • anonymous
what's the next question
anonymous
  • anonymous
so the final answer is?
anonymous
  • anonymous
.39 or -.64
anonymous
  • anonymous
then you check it in the original equation to make sure it works
anonymous
  • anonymous
it works when i checked it, what's the next question
anonymous
  • anonymous
thats all i have now. ive already check the others thanks for all your help
anonymous
  • anonymous
ok, your welcome if you ever need help let me know

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