how would you simplify a cubed root radical of 25 times the radical of 125

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how would you simplify a cubed root radical of 25 times the radical of 125

Mathematics
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ok, you have 25^(1/3) * 125^(1/2)?
yes
ok, so how are 25 and 125 related?

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Other answers:

Both divisible by 5 and 25?
ok, cool, so 25 = 5^2 and 125 = 5^2
5^3, sorry
oh okay yeah
\[\sqrt[3]{25} \times \sqrt{125} = 25^{1/3} \times 125^{1/2} = 5^{2/3} \times 5^{3/2} = 5^{4/6} \times 5^{9/6} = 5^{13/6}\] Feel free to correct me, this is my first time using this equation maker.
omg it's too long for the page HAHA
what is the equation maker?
all right
the answer is 5^{13/6} sorry it's too long haha
yeah, that's how to do it easily hrwhyhry
okay.. how on earth did you get that though?
so you have 25=5^2, and 125=5^3....so you have (5^2)^(1/3) * (5^3)^(1/2)
you can then add the exponents...here: \[(5^2)^(1/3)\]
ohhhhh oka
y mn
(5^2)^(1/3) --> the square (2) and the (1/3) and now add together, 2/3
okay thank you so much!
so, you got it?
i think soooo
now how would you do x-\[\sqrt[3]{3}\div \sqrt{12}\]
sorry its supposed to be the x- the 3 one
????
just a second
thank you :)
\[(x-\sqrt[3]{3})/\sqrt{12}\]
is that the problem? is it equal to something?
no thats the problem. You only have to simplify it
ok
so what is sqrt(12)?
what are factors of 12?
the square root of 4 times the square root of 3?
right on, so sqrt(4) is simple, sqrt(3) is good because the problem has 3^(1/3)
is the answer 1 over x^1/6 times 2?
1/(x^1/6 * 2)?
yes
\[(x-(3^{1/3}))/(2*(3^{1/2}))\]
i had that... i just dont kmow if u can get rid of the three
so you can separate x and -3^(1/3) because they have the same denominator and they are part of a subtraction operation
ok...
thank u for the help by the way
first look at 3^(1/3) / (2 * (3^1/2))
np
can you simplify that? focus on the 3's
u can divide 3 by 3 and get one right
when you divide by exponents you and subtract the exponents from values with the same base
so 3^(1/3) / 3^(1/2) is 3^(1/3) * 3^-(1/2)...can you can add these exponents --> 1/3 = 2/6, 1/2 = 3/6, need to have similar fractions....so 2/6 - 3/6 = -1/6
so you have 3^(-1/6)
which is 1/(3^1/6)
yes and u have to bring it below the division sign since it is negative?>
yeah, like in the last message
is the answer x over 3^1/6 *2
wait, x-1
(x-1)/(2*(3^1/6))
\[(x-1)/(2*(3^1/6))\]
\[(x-1)/(2*(3^{1/6}))\]
how's that look?
Thank you sooo much! I think thats right.....

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