anonymous 5 years ago please solve 3(n+1)/7 is equal to or greater than n+4/5

1. anonymous

$\frac{{3}(n+1)}{7}\geq\frac{(n+4)}{5}$ Playing with the equation editor. Still there?

2. anonymous

$n \le -7\div5$

3. anonymous

Hmm. I'm getting a different answer. Check my work: $\frac{5}{1}*\frac{7}{1}*\frac{{3}(n+1)}{7}\geq\frac{5}{1}*\frac{7}{1}*\frac{(n+4)}{5}$

4. anonymous

$5(3n+3)\geq{7n+28}\Rightarrow15n+15\geq{7n+28}$

5. anonymous

$8n\geq13\Rightarrow{{n}{\geq}\frac{13}{8}}$

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