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anonymous
 5 years ago
How do you find the second partial derivative of f(x,y)=cos^2^xsin^2^y?
anonymous
 5 years ago
How do you find the second partial derivative of f(x,y)=cos^2^xsin^2^y?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its impossible because the formula is wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0were do you get asomthing like that lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's f(x,y)=cos(squared)xsin(squared)y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How did you get that??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no that's why i'm asking... lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can not tell you cuz ther is diff way to do it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and i do not know how he did it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How do you find the second partial derivative of f(x,y)=cos(squared)xsin(squared)y?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0with respect to what?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we start with fx, and fy, then we get fxx, fxy, fyx and fyy, notice that fxy = fyx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0make me your fan and more information will come soon

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok with respect to what so you want all the partial derivatives? ok one sec

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0with respect to all of them lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i will do this on paper

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do do a partial derivative in respect to everything?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0fx = sin^2 y * 2 cos x (sin x), treat y as a constant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then it is in respect to x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats first partial wrt to x , wrt means with respect to

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0fy = cos^2 x * 2 sin y cos y (treat x as a constant)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what is so difficult about this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I didn't know how to do it obviously...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now we find fxx, fxy, fyx, and fyy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats cool, it turns out fxy = fyx always

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first fundamental theorem of partial derivatives
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