anonymous
  • anonymous
How do you find the second partial derivative of f(x,y)=cos^2^xsin^2^y?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
its impossible because the formula is wrong
anonymous
  • anonymous
his yes it is
anonymous
  • anonymous
were do you get asomthing like that lol

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anonymous
  • anonymous
it's f(x,y)=cos(squared)xsin(squared)y
anonymous
  • anonymous
answer is 6
anonymous
  • anonymous
How did you get that??
anonymous
  • anonymous
easy you do not know
anonymous
  • anonymous
no that's why i'm asking... lol
anonymous
  • anonymous
i can not tell you cuz ther is diff way to do it
anonymous
  • anonymous
and i do not know how he did it
anonymous
  • anonymous
okay thanks
anonymous
  • anonymous
whats the question
anonymous
  • anonymous
How do you find the second partial derivative of f(x,y)=cos(squared)xsin(squared)y?
anonymous
  • anonymous
with respect to what?
anonymous
  • anonymous
we start with fx, and fy, then we get fxx, fxy, fyx and fyy, notice that fxy = fyx
anonymous
  • anonymous
make me your fan and more information will come soon
anonymous
  • anonymous
thanks lol
anonymous
  • anonymous
ok with respect to what so you want all the partial derivatives? ok one sec
anonymous
  • anonymous
with respect to all of them lol
anonymous
  • anonymous
i will do this on paper
anonymous
  • anonymous
thanks a lot
anonymous
  • anonymous
didnt post?
anonymous
  • anonymous
how do do a partial derivative in respect to everything?
anonymous
  • anonymous
nope...
anonymous
  • anonymous
fx = sin^2 y * 2 cos x (-sin x), treat y as a constant
anonymous
  • anonymous
then it is in respect to x
anonymous
  • anonymous
yes
anonymous
  • anonymous
thats first partial wrt to x , wrt means with respect to
anonymous
  • anonymous
fy = cos^2 x * 2 sin y cos y (treat x as a constant)
anonymous
  • anonymous
oh. ok
anonymous
  • anonymous
so what is so difficult about this?
anonymous
  • anonymous
I didn't know how to do it obviously...
anonymous
  • anonymous
benito, not nice
anonymous
  • anonymous
Thanks cantorset!!!
anonymous
  • anonymous
now we find fxx, fxy, fyx, and fyy
anonymous
  • anonymous
whats cool, it turns out fxy = fyx always
anonymous
  • anonymous
i see
anonymous
  • anonymous
first fundamental theorem of partial derivatives

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