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its impossible because the formula is wrong
his yes it is
were do you get asomthing like that lol
answer is 6
How did you get that??
easy you do not know
no that's why i'm asking... lol
i can not tell you cuz ther is diff way to do it
and i do not know how he did it
whats the question
How do you find the second partial derivative of f(x,y)=cos(squared)xsin(squared)y?
with respect to what?
we start with fx, and fy, then we get fxx, fxy, fyx and fyy, notice that fxy = fyx
make me your fan and more information will come soon
ok with respect to what so you want all the partial derivatives? ok one sec
with respect to all of them lol
i will do this on paper
thanks a lot
how do do a partial derivative in respect to everything?
fx = sin^2 y * 2 cos x (-sin x), treat y as a constant
then it is in respect to x
thats first partial wrt to x , wrt means with respect to
fy = cos^2 x * 2 sin y cos y (treat x as a constant)
so what is so difficult about this?
I didn't know how to do it obviously...
benito, not nice
now we find fxx, fxy, fyx, and fyy
whats cool, it turns out fxy = fyx always
first fundamental theorem of partial derivatives