find the equation of a line containing the given point and having the given slope (4,4) m= 3/8

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find the equation of a line containing the given point and having the given slope (4,4) m= 3/8

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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hello, ok, do you have the slope-intercept equation? (x,y) = (4,4) is the point and m=3/8
4 = (3/8) * 4 + b, solve for b. Therefore, b = 4 - (3/8)*4
b = (8/8)*4 - (3/8)*4 = (5/8)*4 = 5/2 = 2.5

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did this help?
yes but i am still confused on the fraction part ?
oh, the 8/8 part?
that is just for easier operation. you have (3/8)*4, which you could convert to 12/8, then convert 4 to 32/8, right?
but to get to 32/8, you multiply 4 by (8/8). because both values are 4 * (some fraction)... you have 4* ( 8/8 - 3/8 ) which is 4 *( 5/8 )
this reduces the actual work you do, because you didn't have to obtain the product of 4 * 8/8

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