anonymous
  • anonymous
Kyle has three short straws, four medium straws, and six long straws. If he randomly draws two straws, one at a time without replacement, what is the probability that both are short straws? A) 1/26 B) 3/52 C) 6/169 D) 9/169
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
lets call these SSS MMMM LLL LLL for short , medium and long
anonymous
  • anonymous
so the first straw, you have a probability of 3 / 13 of picking a short straw. the next straw, now you only have 12 straws since you already picked a short straw from last choice. so now you have 2/ 12 of picking a short straw so 3/13 * 2 / 12
anonymous
  • anonymous
more generally, the probability of the conjunction (AND) of two events is P ( A & B ) = P ( A) * P ( B | A) , P(B|A) means the probability of given that A has occurred already. So here we have probability ( short straw on first draw & short straw on second draw) = P(straw on first draw) * P(straw on second draw given first straw was a short one)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
i just want the answer. this is confusing enough

Looking for something else?

Not the answer you are looking for? Search for more explanations.