A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
dy/dx=y^24y+3
find the exact solution and plot a slope field
so i got 2 roots y=4 and y=1 and my critical points are x=1 and x=3
where to go from here?
anonymous
 5 years ago
dy/dx=y^24y+3 find the exact solution and plot a slope field so i got 2 roots y=4 and y=1 and my critical points are x=1 and x=3 where to go from here?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits{1 \over y^24y+3} \quad dy = \int\limits 1 \quad dx\] using partial fractions \[{1 \over 2} \int\limits {1 \over y3}  {1 \over y1} \quad dy = \int\limits 1 \quad dx \] and integrating gives \[{1 \over 2} (\log(y3)  \log(y1) =x+c\] using laws of logs \[\log \quad {y3 \over y1} = 2x+c_2\] raising to the powers of e \[{y3 \over y1} = e^{2x+c_2} = Ae^{2x}\] by the simple algebraic rearangement gives \[y = {3Ae^{2x} \over 1Ae^{2x}}\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.