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anonymous
 5 years ago
does anyone know how to do piecewise functions
?
anonymous
 5 years ago
does anyone know how to do piecewise functions ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Go ahead and post a problem. Eventually someone with the talent will probably be able to walk you through the solution. You may have to be patient though, many of the East Coast/UK/Indian posters will have logged off by now.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What I'm saying is  keep checking back.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thank much for the help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(X)=(2/3)x3 if x less than or equal to 3 3x10 if x is greater than 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you need help graphing this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, it appears that you'll be graphing 2 rays. I will follow the slopeintercept equation y=(2/3)x  3. But you'll only graph the part of the line that starts (above or below) 3 on the xaxis. This ray will proceed to the left, it needs a SOLID endpoint. Do you follow?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i dont so u want me to graph y=(2/3)x  3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The other ray (not a full line) will follow the line y=3x10, with a OPEN endpoint above or below the 3 on the xaxis  and proceeds to the right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, finishing a comment. Yes can you graph y=(2/3)x  3 and y=3x10 if you had too. (otherwise I'll go over point  intercept graphing with you.)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Great. Look at the second graph. http://www.wolframalpha.com/input/?i=y%3D3x10+and+y%3D%282%2F3%29x3 Now your going to graph both lines but erase 1/2 of each line where the two lines cross. KEEP the blue line going to the right (for y=3x10 if x>3) and only KEEP the part of the purple line that goes to the left ( for the x<= 3 condition.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i am suppose to erase the bottom part of the blue where they meet and going back

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Correct, DON'T show the blue line left of where the two lines intercect. (Again where using the second graph, not the first).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You'll want to use two different colors or solid and dashed lines.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then what exactly am i doing with the purple line?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The purple line will be the rest of your graph left of the (2,1) intersection point. The net effect is the line looks "bent" like a shallow "v".

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i am not supose to do anything to the purple line?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok ok i thank you guys for all your help!!!!!!!!!!!!......:)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right  if you started out by graphing both lines  you would _erase_ the purple line to the RIGHT of (2,1) > but keep the purple line LEFT of (2,1). Do the same but in reverse for the blue line. So looking at the graph  coming from the right. ONLY blue ray, SOLID purple dot at (2,1) then ONLY purple ray to negative infinity.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0np that is way i am here i am in 8 so if you need help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry  lag in the reply posting.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I found a white board. Go to this URL in another tab. http://www.twiddla.com/491709

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I didn't put in the x or yaxis.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i did that if u can see it on the board

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you think you got it now the function follows the blue line for all x inputs above 3 and the purple line for inputs 3 or less. The output "steps" over to another rule (function) at x=3.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i do...and i thank u alot for ur help...:)
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