A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

does anyone know how to do piecewise functions ?

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Go ahead and post a problem. Eventually someone with the talent will probably be able to walk you through the solution. You may have to be patient though, many of the East Coast/UK/Indian posters will have logged off by now.

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What I'm saying is - keep checking back.

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok thank much for the help

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f(X)=(2/3)x-3 if x less than or equal to 3 3x-10 if x is greater than 3

  5. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Do you need help graphing this?

  6. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  7. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    OK, it appears that you'll be graphing 2 rays. I will follow the slope-intercept equation y=(2/3)x - 3. But you'll only graph the part of the line that starts (above or below) 3 on the x-axis. This ray will proceed to the left, it needs a SOLID end-point. Do you follow?

  8. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no i dont so u want me to graph y=(2/3)x - 3?

  9. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The other ray (not a full line) will follow the line y=3x-10, with a OPEN endpoint above or below the 3 on the x-axis - and proceeds to the right.

  10. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Sorry, finishing a comment. Yes can you graph y=(2/3)x - 3 and y=3x-10 if you had too. (otherwise I'll go over point - intercept graphing with you.)

  11. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i can individually

  12. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Great. Look at the second graph. http://www.wolframalpha.com/input/?i=y%3D3x-10+and+y%3D%282%2F3%29x-3 Now your going to graph both lines but erase 1/2 of each line where the two lines cross. KEEP the blue line going to the right (for y=3x-10 if x>3) and only KEEP the part of the purple line that goes to the left ( for the x<= 3 condition.

  13. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so i am suppose to erase the bottom part of the blue where they meet and going back

  14. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ahhh

  15. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Correct, DON'T show the blue line left of where the two lines intercect. (Again where using the second graph, not the first).

  16. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You'll want to use two different colors or solid and dashed lines.

  17. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then what exactly am i doing with the purple line?

  18. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The purple line will be the rest of your graph left of the (2,-1) intersection point. The net effect is the line looks "bent" like a shallow "v".

  19. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ahhhhhhh why lol jk

  20. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ???

  21. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so i am not supose to do anything to the purple line?

  22. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no

  23. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok ok i thank you guys for all your help!!!!!!!!!!!!......:)

  24. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Right - if you started out by graphing both lines - you would _erase_ the purple line to the RIGHT of (2,-1) --> but keep the purple line LEFT of (2,-1). Do the same but in reverse for the blue line. So looking at the graph - coming from the right. ONLY blue ray, SOLID purple dot at (2,-1) then ONLY purple ray to negative infinity.

  25. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    np that is way i am here i am in 8 so if you need help

  26. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Sorry - lag in the reply posting.

  27. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lol its ok

  28. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I found a white board. Go to this URL in another tab. http://www.twiddla.com/491709

  29. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i am there

  30. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I didn't put in the x or y-axis.

  31. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok i did that if u can see it on the board

  32. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Do you think you got it now the function follows the blue line for all x inputs above 3 and the purple line for inputs 3 or less. The out-put "steps" over to another rule (function) at x=3.

  33. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So you set?

  34. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes i do...and i thank u alot for ur help...:)

  35. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    OK - good luck.

  36. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.