## anonymous 5 years ago find the limit. Lim x-->1....(2x^4-6x^3+x^2+3)/(x-1)

1. anonymous

If you plug x=1 into your equation, you'll get 0/0. That means you can apply L'Hospital's rule (take the derivative of the numerator and denominator). Applying L'Hospital's rule, you'll get $\lim_{x \rightarrow 1} 8x^{3}-18x^{2}+2x$ Now you can evaluate your limit.

2. anonymous

thank you