The sum of the lengths of any two sides of a triangle much be greater than the third side. If a triangle has a side that is 14cm and a second side that is 1cm less than twice the third side, what are the possible lengths for the second and third side?
How do i work this problem?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
The first step is always to make equations out of problems like this.
So let's call the sides x, y, and z. You have:
x = 14
y = 2z - 1
z = ?
So you need to determine which values of y and z could make this true. But, you have one more piece of information: the sume of the lengths of any two sides must be greater than the third side. We have one side that we know and one that we have in terms of another. So we know that:
x + y > z
14 + 2z - 1 > z
2z + 13 > z
Now you can solve to figure out the range of values that z can take, and then you can use that to calculate the range of values that y can take. Does that help?